我有一些不同字符串的文件(从prod中获取大约100.000)。需要找出99%,99.9%的函数来处理该文件中的每个字符串。
我尝试使用 jmh 来编写基准。但是,我能够仅为批处理函数(处理整个文件)或仅针对具有一个特定字符串的所需函数找出所需的百分位数。
public String process1(String str){
...process...
}
public String processBatch(List<String> strings){
for (String str: strings){
process1(str)
}
}
另外,我试图通过@param设置整个字符串列表。这使jmh为每个字符串运行了几十次迭代,但没有找到所需的结果。
jmh中有什么可以帮助找到所需的统计数据吗?如果没有,可以使用什么工具?
答案 0 :(得分:2)
这是你在找什么?
@Warmup(iterations = 1, time = 5, timeUnit = TimeUnit.SECONDS)
@Measurement(iterations = 1, time = 5, timeUnit = TimeUnit.SECONDS)
@Fork(1)
@State(Scope.Benchmark)
public class MyBenchmark {
ClassUnderBenchmark classUnderBenchmark = new ClassUnderBenchmark();
@State(Scope.Benchmark)
public static class MyTestState {
int counter = 0;
List<String> list = Arrays.asList("aaaaa", "bbbb", "ccc");
String currentString;
@Setup(Level.Invocation)
public void init() throws IOException {
this.currentString = list.get(counter++);
if (counter == 3) {
counter = 0;
}
}
}
@Benchmark
@Threads(1)
@BenchmarkMode(Mode.SampleTime)
public void test(MyBenchmark.MyTestState myTestState) {
classUnderBenchmark.toUpper(myTestState.currentString);
}
public static class ClassUnderBenchmark {
Random r = new Random();
public String toUpper(String name) {
try {
Thread.sleep(r.nextInt(100));
} catch (InterruptedException e) {
e.printStackTrace();
}
return name.toUpperCase();
}
}
public static void main(String[] args) throws RunnerException {
Options opt = new OptionsBuilder()
.include(MyBenchmark.class.getSimpleName())
.jvmArgs("-XX:+UseG1GC", "-XX:MaxGCPauseMillis=50")
.build();
new Runner(opt).run();
}
}
请参阅javadoc(org.openjdk.jmh.annotations.Mode):
/**
* <p>Sample time: samples the time for each operation.</p>
*
* <p>Runs by continuously calling {@link Benchmark} methods,
* and randomly samples the time needed for the call. This mode automatically adjusts the sampling
* frequency, but may omit some pauses which missed the sampling measurement. This mode is time-based, and it will
* run until the iteration time expires.</p>
*/
SampleTime("sample", "Sampling time"),
此测试将为您提供输出:
Result "test":
N = 91
mean = 0,056 ±(99.9%) 0,010 s/op
Histogram, s/op:
[0,000, 0,010) = 6
[0,010, 0,020) = 9
[0,020, 0,030) = 3
[0,030, 0,040) = 11
[0,040, 0,050) = 8
[0,050, 0,060) = 11
[0,060, 0,070) = 9
[0,070, 0,080) = 9
[0,080, 0,090) = 14
Percentiles, s/op:
p(0,0000) = 0,003 s/op
p(50,0000) = 0,059 s/op
p(90,0000) = 0,092 s/op
p(95,0000) = 0,095 s/op
p(99,0000) = 0,100 s/op
p(99,9000) = 0,100 s/op
p(99,9900) = 0,100 s/op
p(99,9990) = 0,100 s/op
p(99,9999) = 0,100 s/op
p(100,0000) = 0,100 s/op
Benchmark Mode Cnt Score Error Units
MyBenchmark.test sample 91 0,056 ± 0,010 s/op