Question

我正在处理的程序输出该符号的直角三角形，边长等于该数字。它应该做的是终止，如果你输入0，否则它应该再次要求新的输入。

所以我的问题是如果你输入0我怎么能让它终止，否则要求另一个输入？我知道我可能需要使用while循环。但是我该怎么改呢？

这是我的代码：

#include <assert.h>
#include <stdio.h>
#include <stdlib.h>

int main()
{
    char s;         /*s is symbol (the input)*/
    int a, b, n;    /*n is number of rows (the input)*/

    printf("Please type the symbol of the triangle:...\n"); /*Ask for symbol input*/
    scanf_s("%c", &s, 1);
    printf("Please type a positive non-zero number between 5 and 35:...\n"); /*Ask for number of rows input*/
    scanf_s("%d", &n);
    assert(n >= 5 && n <= 35);

    for (a = 1; a <= n; a++) /*How many rows to display+create*/
    {
        for (b = 1; b <= a; b++)
        {
            printf("%c", s);
        }
        printf("\n");
    }
    system("PAUSE");
}

Answer 1

你可以使用循环来做到这一点。

#include <stdio.h>
#include <stdlib.h>

#ifndef _MSC_VER
/* passing extra arguments to scanf is not harmful */
#define scanf_s scanf
#endif

int main(void)
{
    char s;         /*s is symbol (the input)*/
    int a, b, n;    /*n is number of rows (the input)*/

    do {
        printf("Please type the symbol of the triangle:...\n"); /*Ask for symbol     input*/
        scanf_s("%c", &s, 1);
        printf("Please type a positive non-zero number between 5 and 35:...\n");     /*Ask for number of rows input*/
        scanf_s("%d", &n);
        if(n >= 5 && n <= 35)
        {
            for (a = 1; a <= n; a++)/*How many rows to display+create*/
            {
                for (b = 1; b <= a; b++)
                {
                    printf("%c", s);
                }
                printf("\n");
            }
        }
        while ((a = getchar()) != '\n' && a != EOF); /* remove the newline character from standard input buffer */
    } while (n != 0);
    system("PAUSE");
}

该符号的直角三角形，边长等于该数字

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