Question

我有一个使用WCF Rest客户端生成的简单JSON，但是当我尝试反序列化响应时，我在JSON.Net中收到错误NullReferenceException。我有以下JSON：

{"Code":-2146232800,"ExceptionType":"IOException","Message":"Msg","Stacktrace":"Some"}

以下课程：

[DataContract]
public class FileUploadError
{
    public FileUploadError(Exception exception)
    {
        Code = exception.HResult;
        ExceptionType = exception.GetType().Name;
        Message = GetMessage(exception);
        Stacktrace = exception.StackTrace;
        if (exception.Data.Count > 0)
        {
            Data = string.Join(Environment.NewLine, exception.Data.Cast<DictionaryEntry>().Select(x => x.Key + "=" + x.Value));
        }
    }

    private string GetMessage(Exception exception)
    {
        if (exception.InnerException == null)
        {
            return exception.Message;
        }
        const string delimiter = "->";
        var sb = new StringBuilder(1024);
        for (var ex = exception; ex != null; ex = ex.InnerException)
        {
            sb.Append(ex.Message).Append(delimiter);
        }
        sb.Length -= delimiter.Length;
        return sb.ToString();
    }

    [DataMember(IsRequired = true)]
    [JsonProperty("Code", NullValueHandling = NullValueHandling.Ignore)]
    public int Code { get; set; }
    [DataMember(IsRequired = true)]
    [JsonProperty("ExceptionType", NullValueHandling = NullValueHandling.Ignore)]
    public string ExceptionType { get; set; }
    [DataMember(EmitDefaultValue = false)]
    [JsonProperty("Message", NullValueHandling = NullValueHandling.Ignore)]
    public string Message { get; set; }
    [DataMember(EmitDefaultValue = false)]
    [JsonProperty("Stacktrace", NullValueHandling = NullValueHandling.Ignore)]
    public string Stacktrace { get; set; }
    [DataMember(EmitDefaultValue = false)]
    [JsonProperty("Data", NullValueHandling = NullValueHandling.Ignore)]
    public string Data { get; set; }
}

然后我反序化它：

const string text = "{\"Code\":-2146232800,\"ExceptionType\":\"IOException\",\"Message\":\"Msg\",\"Stacktrace\":\"Some\"}";
var obj = JsonConvert.DeserializeObject<FileUploadError>(text);

并获得subj错误。在新的控制台应用程序中重现，如果需要，我可以提供。 JSON很简单，为什么我收到这个错误？

示例：https://dotnetfiddle.net/76FJd0

堆栈跟踪：

System.Reflection.TargetInvocationException: Exception has been thrown by the target of an invocation. ---> System.NullReferenceException: Object reference not set to an instance of an object.
   at FileUploadError..ctor(Exception exception) in d:\Windows\Temp\nclgvim3.0.cs:line 28
   --- End of inner exception stack trace ---
   at System.RuntimeMethodHandle.InvokeMethod(Object target, Object[] arguments, Signature sig, Boolean constructor)
   at System.Reflection.RuntimeConstructorInfo.Invoke(BindingFlags invokeAttr, Binder binder, Object[] parameters, CultureInfo culture)
   at System.Reflection.ConstructorInfo.Invoke(Object[] parameters)
   at Newtonsoft.Json.Serialization.JsonSerializerInternalReader.CreateObjectFromNonDefaultConstructor(JsonReader reader, JsonObjectContract contract, JsonProperty containerProperty, ConstructorInfo constructorInfo, String id)
   at Newtonsoft.Json.Serialization.JsonSerializerInternalReader.CreateObject(JsonReader reader, Type objectType, JsonContract contract, JsonProperty member, JsonContainerContract containerContract, JsonProperty containerMember, Object existingValue)
   at Newtonsoft.Json.Serialization.JsonSerializerInternalReader.CreateValueInternal(JsonReader reader, Type objectType, JsonContract contract, JsonProperty member, JsonContainerContract containerContract, JsonProperty containerMember, Object existingValue)
   at Newtonsoft.Json.Serialization.JsonSerializerInternalReader.Deserialize(JsonReader reader, Type objectType, Boolean checkAdditionalContent)
   at Newtonsoft.Json.JsonSerializer.DeserializeInternal(JsonReader reader, Type objectType)
   at Newtonsoft.Json.JsonConvert.DeserializeObject(String value, Type type, JsonSerializerSettings settings)
   at Newtonsoft.Json.JsonConvert.DeserializeObject[T](String value, JsonSerializerSettings settings)
   at Program.Main(String[] args)

Answer 1

您需要向FileUploadError类添加公共无参数构造函数：

public class FileUploadError
{
    public FileUploadError()
    {
    }

或者，您可以将其设为私有并使用[JsonConstructor]：

public class FileUploadError
{
    [JsonConstructor]
    private FileUploadError()
    {
    }

或者，将其保密并使用ConstructorHandling = ConstructorHandling.AllowNonPublicDefaultConstructor反序列化：

var settings = new JsonSerializerSettings
{
    ConstructorHandling = ConstructorHandling.AllowNonPublicDefaultConstructor
};
var obj = JsonConvert.DeserializeObject<FileUploadError>(text, settings);

使用：

public class FileUploadError
{
    private FileUploadError()
    {
    }

Answer 2

对于那些后来因为OP的特定案例已解决而翻滚的人。

这里是发生错误消息的处理方法。

来源：https://www.newtonsoft.com/json/help/html/SerializationErrorHandling.htm

var errors = new List<string>();

List<DateTime> c = JsonConvert.DeserializeObject<List<DateTime>>(
    yourJsonHere,
    new JsonSerializerSettings
    {
        Error = delegate(object sender, ErrorEventArgs args)
        {
            errors.Add(args.ErrorContext.Error.Message);
            args.ErrorContext.Handled = true;
        }
    });

然后errors将包含已发生错误的列表！同时适用于序列化和反序列化！

这样做确实会使您失去上下文！因此，您也可以将其设置为Handled = false。

Newtonsoft json.net反序列化NullReferenceException

2 个答案: