Question

JSON具有复杂的对象，其中一些对象具有名称空间信息，我该如何在Deserialize中对此进行说明。下面的简化示例

{
  "id": "123456",
  "urn:test:params:scim:schemas:extension:PersonBioExtension": {
    "dateOfBirth": "1900-01-01",
    "gender": "MALE",
  }
}

反序列化代码：

Rootobject user = JsonConvert.DeserializeObject<Rootobject>(textBox1.Text);

课程：

public class Rootobject
{
    public string id { get; set; }
    public TestScimSchemasExtensionBio testScimSchemasExtensionBio { get; set; }
}

public class TestScimSchemasExtensionBio
{
    public string dateOfBirth { get; set; }
    public string gender { get; set; }
}

Answer 1

正如注释中提到的，在将属性序列化为JSON时，您可以使用JsonPropertyAttribute来更改属性的名称。

Json字符串：

{
  "id": "123456",
  "urn:test:params:scim:schemas:extension:PersonBioExtension": {
    "dateOfBirth": "1900-01-01",
    "gender": "MALE",
  }
}

型号：

public class Model
{
    [JsonProperty("id")]
    public string Id { get; set; }

    [JsonProperty("urn:test:params:scim:schemas:extension:PersonBioExtension")]
    public TestScimSchemasExtensionBio TestScimSchemasExtensionBio { get; set; }
}

public class TestScimSchemasExtensionBio
{
    [JsonProperty("dateOfBirth")]
    public DateTimeOffset DateOfBirth { get; set; }

    [JsonProperty("gender")]
    public string Gender { get; set; }
}

反序列化：

string json = @"{
  ""id"": ""123456"",
  ""urn:test:params:scim:schemas:extension:PersonBioExtension"": {
    ""dateOfBirth"": ""1900-01-01"",
    ""gender"": ""MALE"",
  }
}";

Model model = JsonConvert.DeserializeObject<Model>(json);

Newtonsoft json将复杂对象反序列化为具有不同名称的类

1 个答案: