Question

我有2个查询返回2个结果集。如何将这两个查询组合起来得到一个结果？

第一次查询：

SELECT *
FROM Base base
INNER JOIN Child child ON child.base_id = base.id
where base.`status` = "active" and base.application = "template";

第二次查询：

SELECT *
FROM Base base
WHERE base.`status` = "active" and base.application = "template" and base.role = "public" ;

请帮忙。

Answer 1

您可以尝试使用UNION：

SELECT col1, col2, col3, col4....
FROM Base base
INNER JOIN Child child ON child.base_id = base.id
where base.`status` = "active" and base.application = "template"

UNION

SELECT col1, col2, col3, col4....
FROM Base base
WHERE base.`status` = "active" and base.application = "template" and base.role = "public" ;

请注意，如果您希望获得两个查询中的重复元素，则可以使用UNION ALL。

使用UNION时，请确保查询结果的列数相同。

Answer 2

试试这个：

SELECT *
FROM Base base
INNER JOIN Child child ON child.base_id = base.id
WHERE ( base.`status` = "active" 
AND base.application = "template" )or (base.`status` = "active" and base.application = "template" and base.role = "public");

Mysql - 结合2个SQL查询

2 个答案: