Question

我现在有2个查询，如果可能，我希望将其合并为1个。

我已经在Tickets_Open表中存储了已打开的票证，而在Tickets_Closed中已关闭了票证。两个表都有“ Date_Requested”和“ Date_Completed”列。我需要计算每天请求和完成的门票数量。

我的机票请求计数查询如下：

SELECT SUM(Count) AS TotalOpen, Date FROM(
 SELECT COUNT(Ticket_Request_Code) AS Count, Date_Requested AS Date
 FROM Tickets_Closed
 WHERE Date_Requested >='2018-01-01 00:00:00'
 GROUP BY(Date_Requested)
 UNION
 SELECT COUNT(Work_Request_Code) AS Count, Date_Requested AS Date
 FROM Tickets_Open
 WHERE Date_Requested >='2018-01-01 00:00:00'
 GROUP BY(Date_Requested)
) AS t1 GROUP BY Date ORDER BY `t1`.`Date` DESC

我的票完成计数查询如下：

SELECT COUNT(Ticket_Request_Code) AS CountClosed, Date_Completed AS Date
FROM Tickets_Closed
Where Date_Completed >='2018-01-01 00:00:00'
GROUP BY(Date_Completed)

两个查询都返回正确的结果。对于打开，它返回列标题为Date和TotalOpen。如果要关闭，则返回列标题为Date和CountClosed。

是否可以使用以下列标题Date，TotalOpen，CountClosed返回它。

Answer 1

您可以将它们组合为：

SELECT Date, SUM(isopen) as isopen, SUM(isclose) as isclose
FROM ((SELECT date_requested as date, 1 as isopen, 0 as isclose
       FROM Tickets_Closed
       WHERE Date_Requested >= '2018-01-01'
      ) UNION ALL
      (SELECT date_requested, 1 as isopen, 0 as isclose
       FROM Tickets_Open
       WHERE Date_Requested >= '2018-01-01'
      ) UNION ALL
      (SELECT date_closed as date, 0 as isopen, 1 as isclose
       FROM Tickets_Closed
       WHERE date_closed >= '2018-01-01'
      )
     ) t
GROUP BY Date
ORDER BY Date DESC;

这假设Ticket_Request_Code和Work_Request_Code不是NULL。如果确实使用COUNT()检查NULL值，则将条件添加到每个子查询的WHERE子句中。

Answer 2

此查询也使用日期上的FULL OUTER JOIN，但它正确地将打开/关闭计数加在一起以提供TotalOpen计数。对于一天中没有关闭任何票证的情况，这还将处理可能的NULL值。

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将2个SQL查询合并为1个查询

2 个答案: