Question

这是我的代码：

$d = new DateTime('2016-07-14');
$inc = new DateInterval('P1D');
$dateOptions = '';
//1=monday 2=tuesday 3=wednesday
$required = array(1,2,3,4);
$counter = $week = 0;
for ($i=0; $i<40; ++$i){
    $d = $d->add($inc);
    if (in_array($d->format('w'), $required)) {
        if($counter % 4 == 0){
            echo ($week + 1) . "<br />";
            ++$week;
        }
        $t = $d->format('l, F d, Y');
        echo $t . "<br />";   
        ++$counter;
    }
}

这是输出：

1
Monday, July 18, 2016
Tuesday, July 19, 2016
Wednesday, July 20, 2016
Thursday, July 21, 2016
2
Monday, July 25, 2016
Tuesday, July 26, 2016
Wednesday, July 27, 2016
Thursday, July 28, 2016

我希望输出如下：

1
Thursday, July 14, 2016
2
Monday, July 18, 2016
Tuesday, July 19, 2016
Wednesday, July 20, 2016
Thursday, July 21, 2016
3
Monday, July 25, 2016
Tuesday, July 26, 2016
Wednesday, July 27, 2016
Thursday, July 28, 2016

需要对代码进行哪些更改才能允许星期四在第一周输出？

提前致谢！

Answer 1

您正在递增从0初始化的计数器。因此更改为周数
您要求从给定日期开始，但在循环内增加它。所以在循环之前减去它

所以修改后的代码：

<?php
$d = new DateTime('2016-07-14');
$inc = new DateInterval('P1D');

$d = $d->sub($inc); // You need the start date from 14

$required = array(1,2,3,4);
$week = 0;
for ($i=0; $i<40; ++$i){
    $d = $d->add($inc);
    $weekNumber = $d->format('w');
    if (in_array($weekNumber, $required)) {
        if(!($weekNumber-1) % 4){   //Don't calculate the counter, but the week number
            echo (++$week) . "<br />";
        }
        $t = $d->format('l, F d, Y');
        echo $t . "<br />";   
    }
}

输出：

Thursday, July 14, 2016
1
Monday, July 18, 2016
Tuesday, July 19, 2016
Wednesday, July 20, 2016
Thursday, July 21, 2016
2
Monday, July 25, 2016
Tuesday, July 26, 2016
Wednesday, July 27, 2016
Thursday, July 28, 2016
3
Monday, August 01, 2016
Tuesday, August 02, 2016
Wednesday, August 03, 2016
Thursday, August 04, 2016
4
Monday, August 08, 2016
Tuesday, August 09, 2016
Wednesday, August 10, 2016
Thursday, August 11, 2016
5
Monday, August 15, 2016
Tuesday, August 16, 2016
Wednesday, August 17, 2016
Thursday, August 18, 2016
6
Monday, August 22, 2016

您的Eval

Answer 2

使用以下代码，

for ($i=0; $i<40; ++$i){
    if($i==0)
    {
        echo ($week + 1) . "<br />";
            ++$week;
    $t = $d->format('l, F d, Y');
        echo $t . "<br />";  

    }
    $d = $d->add($inc);
    if (in_array($d->format('w'), $required)) {
        if($counter % 4 == 0){
            echo ($week + 1) . "<br />";
            ++$week;
        }
        $t = $d->format('l, F d, Y');
        echo $t . "<br />";   
        ++$counter;
    }
}

<强>输出：

1
Thursday, July 14, 2016
2
Monday, July 18, 2016
Tuesday, July 19, 2016
Wednesday, July 20, 2016
Thursday, July 21, 2016
3
Monday, July 25, 2016
Tuesday, July 26, 2016
Wednesday, July 27, 2016
Thursday, July 28, 2016

Answer 3

这是我使用的最终代码：

$d = new DateTime('2016-08-29');
$inc = new DateInterval('P1D');

$d = $d->sub($inc); 

$required = array(2,4); //1=monday 2=tuesday 3=wednesday 4=thursday 5=friday
$howmany = count($required);

$week = 0;

for ($i=0; $i<120; ++$i){

    $d = $d->add($inc);
    if (in_array($d->format('w'), $required)) {
        if($counter % $howmany == 0){
            echo ($week + 1) . "<br />";
            ++$week;
        }

    $t = $d->format('l, F d, Y');
        echo $t . "<br />";   
        ++$counter;
    }
}

感谢您的帮助！

在PHP中生成日期

3 个答案: