我正在尝试使用Pandas绘制给定输入的散点图。我收到以下错误。
输入:
tweetcricscore 34 #afgvssco 51
tweetcricscore 23 #afgvszim 46
tweetcricscore 24 #banvsire 12
tweetcricscore 456 #banvsned 46
tweetcricscore 653 #canvsnk 1
tweetcricscore 789 #cricket 178
tweetcricscore 625 #engvswi 46
tweetcricscore 86 #hkvssco 23
tweetcricscore 3 #indvsban 1
tweetcricscore 87 #sausvsvic 8
tweetcricscore 98 #wt20 56
代码:
import numpy as np
import matplotlib.pyplot as plt
from pylab import*
import math
from matplotlib.ticker import LogLocator
import pandas as pd
df = pd.read_csv('input.csv', header = None)
df.columns = ['col1','col2','col3','col4']
plt.scatter(x='col2', y='col4', s=120, c='b', label='Highly Active')
plt.legend(loc='upper right')
plt.xlabel('Freq (x)')
plt.ylabel('Freq(y)')
#plt.gca().set_xscale("log")
#plt.gca().set_yscale("log")
plt.show()
我试图在散点图中将col [1]和col [3]数据点作为对绘制。
错误
Traceback (most recent call last):
File "00_scatter_plot.py", line 14, in <module>
plt.scatter(x='col2', y='col3', s=120, c='b', label='Highly Active')
File "/usr/lib/pymodules/python2.7/matplotlib/pyplot.py", line 3087, in scatter
linewidths=linewidths, verts=verts, **kwargs)
File "/usr/lib/pymodules/python2.7/matplotlib/axes.py", line 6337, in scatter
self.add_collection(collection)
File "/usr/lib/pymodules/python2.7/matplotlib/axes.py", line 1481, in add_collection
self.update_datalim(collection.get_datalim(self.transData))
File "/usr/lib/pymodules/python2.7/matplotlib/collections.py", line 185, in get_datalim
offsets = np.asanyarray(offsets, np.float_)
File "/usr/local/lib/python2.7/dist-packages/numpy/core/numeric.py", line 514, in asanyarray
return array(a, dtype, copy=False, order=order, subok=True)
ValueError: could not convert string to float: col2
答案 0 :(得分:1)
这是您的错误消息:
File "00_scatter_plot.py", line 14, in <module>
plt.scatter(x='col2', y='col3', s=120, c='b', label='Highly Active')
ValueError: could not convert string to float: col2
正如您所看到的,您正在尝试将字符串“col2”转换为float。
通过查看您的代码,您似乎想要这样的事情:
plt.scatter(x=df['col2'], y=df['col4'], s=120, c='b', label='Highly Active')
而不是:
plt.scatter(x='col2', y='col4', s=120, c='b', label='Highly Active')
答案 1 :(得分:1)