我的TimerTask函数无法更新label.setText

时间:2016-05-11 11:51:38

标签: java javafx timertask

我正在写一个涉及计时器的小程序但由于某种原因我无法让TimerTask更新我的Label.setText的值

public class Main extends Application  {


Label TimerLabel;
/* Create a Button named button */
Button button;
/* Create three Radiobuttons named Radio1,Radio2,Radio3 */
RadioButton Radio1, Radio2, Radio3;

Timer QuestionTimer = new Timer();
TimerTask QuestionTick = new TimerTask() {
    @Override
    public void run() {
        TimerLabel.setText(String.valueOf(Integer.valueOf(TimerLabel.getText())+1));
    }
};

public static void main(String[] args) {
    launch(args);
}

/*UI Part*/
@Override
public void start(Stage primaryStage) throws Exception {


    /*Window(Stage) Title is set to "Try 1"*/
    primaryStage.setTitle("Try 1");

    /*Button properties*/
    button = new Button();
    button.setText("Click Me");


    //Radio Button
    Radio1 = new RadioButton();
    Radio1.setText("Click Me 1");
    Radio1.setOnAction(e->{
        System.out.println("Radio Button Clicked");
    });

    Radio2 = new RadioButton();
    Radio2.setText("Click Me 2");
    Radio2.setOnAction(e->{
        System.out.println("Radio Button 2 Clicked");
    });

    Radio3 = new RadioButton();
    Radio3.setText("Click Me 3");
    Radio3.setOnAction(e->{
        System.out.println("Radio Button 3 Clicked");
    });

    TimerLabel = new Label();
    TimerLabel.setText("0");


    /*Here my layout is defined */
    Pane Buttonlayout = new Pane();
    button.setLayoutX(200);
    button.setLayoutY(200);
    Radio1.setLayoutX(15);
    Radio1.setLayoutY(20);
    Radio2.setLayoutX(15);
    Radio2.setLayoutY(40);
    Radio3.setLayoutX(15);
    Radio3.setLayoutY(60);
    TimerLabel.setLayoutX(100);
    TimerLabel.setLayoutY(20);
    Buttonlayout.getChildren().add(button);
    Buttonlayout.getChildren().add(Radio1);
    Buttonlayout.getChildren().add(Radio2);
    Buttonlayout.getChildren().add(Radio3);
    Buttonlayout.getChildren().add(TimerLabel);

    /*Here we define the scene (aka everything inside the stage (inside the window))*/
    Scene scene1 = new Scene(Buttonlayout,300,250);


    primaryStage.setScene(scene1);
    primaryStage.show();

    QuestionTimer.scheduleAtFixedRate(QuestionTick,1000,1000);
}

}

那就是我的代码,我知道大部分内容似乎都很愚蠢,但我首先想开始对定时器进行编程,而且它没有用。任何形式的帮助将不胜感激

1 个答案:

答案 0 :(得分:1)

从您看到的代码中,您正在使用java.util.Timer类。文档说明Implementation note: All constructors start a timer thread.不应该从另一个线程更新JavaFX UI,这是您使用计时器进行的操作。

不是直接更新UI,而是使用Platform.runLater(Runnable)在主JavaFX线程上安排UI任务。

javafx.application.Platform.runLater(new Runnable() {
  @Override
  public void run() {
    TimerLabel.setText(String.valueOf(Integer.valueOf(TimerLabel.getText())+1));
  }
}

并请,帮自己一个忙,摆脱链接的方法。当Integer.valueOf抛出Exception时,它将使调试变得更容易。

String timer_label = TimerLabel.getText();
Integer timer_int = Integer.valueOf(timer_label);
String timer_text = String.valueOf(timer_int + 1);
TimerLabel.setText(timer_text);