Question

我在使用Python 2.7编写的代码时遇到了一些麻烦。它给我一个关于elif语句的语法错误，但是没有解释，我在代码中找不到任何合理的错误。（字体是我定义的方法。）

num = randrange(-25,15)
""" Toxic """
if num >= -25 and num < -10:
        responses = ["Ugh, nasty.", "That was absolutely disgusting.", "My stomach feels like it's going to explode.", "Pardon me if I puke."]
        typeline(responses[randrange(0,4)], "jack")
        return [num, "Jack ate a VERY TOXIC FRUIT and survived.", "Jack ate a VERY TOXIC FRUIT and died."]
""" Mildly poisonous """
elif num >= -10 and num < 0: """ SYNTAX ERROR HERE """
        responses = ["Yuck", "It's kinda bitter.", "Tastes like an unripe banana.", "It's not so bad."]
        typeline(responses[randrange(0,4)], "jack")
        return [num, "Jack ate a MILDLY TOXIC FRUIT and survived.", "Jack ate a MILDLY TOXIC FRUIT and died."]
""" Healthy """
else:
        responses = ["Definitely not too bad", "It's almost kind of tasty!", "Should I make a jam out of this?", "This is my new favorite fruit."]
        typeline(responses[randrange(0,4)], "jack")
        return [num, "Jack ate a HEALTHY FRUIT and was rescued.", "Jack ate HEALTHY FRUIT and survived."]

错误：

  File "<stdin>", line 9
    elif num >= -10 and num < 0:
       ^
SyntaxError: invalid syntax

Answer 1

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之前，您有一个未缩进的三引号字符串文字

elif

""" Mildly poisonous """ elif num >= -10 and num < 0:字符串文字不多行注释。他们创建字符串，只是因为你忽略了生成的字符串对象，Python忽略了这一行。它们仍然是Python语法的一部分;使用它们时，你不能忽略缩进规则。

改为使用正确的"""..."""条评论：

由于语法忽略了完全的注释，因此它们的缩进方式并不重要。

如果您必须使用# Toxic if num >= -25 and num < -10: # ... # Mildly poisonous elif num >= -10 and num < 0: # ... # Healthy else: # ...三重引号字符串作为＆＃39;阻止评论＆＃39;，则必须缩进它们，使其成为""" ... """或if块的一部分放在：

elif

Python中elif语句的语法错误

1 个答案: