Question

我正在编写部分代码（正如标题中所述）。所有的elif都在努力工作到第10行（即elif inc＆lt; = e和inc＆gt; d :)，这是IDLE中突出显示的错误。这是代码：

def calc(a,b,c,d,e,f):
    if inc <= a and inc >= 0:
        tax = 0.10 * income
    elif inc <= b and inc > a:
        tax = (0.10 * a) + (0.15 * (income - a))
    elif inc <= c and inc > b:
        tax = (0.10 * a) + (0.15 * b) + (0.25 * (income - b))
    elif inc <= d and inc > c:
        tax = (0.10 * a) + (0.15 * b) + (0.25 * c) + (0.28 * (income - c)                                           
    elif inc <= e and inc > d:
        tax = (0.10 * a) + (0.15 * b) + (0.25 * c) + (0.28 * d) + (0.33 * \
            (income - d))
    elif inc <= f and inc > e:
        tax = (0.10 * a) + (0.15 * b) + (0.25 * c) + (0.28 * d) + (0.33 * \
            e) + (0.35 * (income - e))
    elif inc > f:
        tax = (0.10 * a) + (0.15 * b) + (0.25 * c) + (0.28 * d) + (0.33 * \
            e) + (0.35 * f) + (0.396 * (income - f)
    tax_str = str(tax)

Answer 1

这一行：

tax = (0.10 * a) + (0.15 * b) + (0.25 * c) + (0.28 * (income - c)

您忘记在最后添加)。

然后，Python将下一行解释为前一行的延续，因此是SyntaxError。

Python - elif语句给出无效的语法错误

1 个答案: