Question

我在数据库中有日期时间数据，并且从我计算的总时数只计算日期而不是时间。我正在使用strtotime进行计算。例如：

$LastDate = '2016-04-27 17:27:28';
$endDate = strtotime($LastDate); // 1461770848

$LastDate = '2016-04-27';
$endDate = strtotime($LastDate); // 1461708000

我只想要第二个值。所以我想从$ LastDate中提取日期。

 ///////////Getting data from Employee Outstation(Travel) details from database/////////////
   $employeeTravel = new EmployeeTravelRecord();     

   $TravelEntryList = $employeeTravel->Find("employee = 2 and (date(travel_date) <= ? and ? <=  date(return_date))",array($req['date_end'],$req['date_start']));

            $startdate = $req['date_start'];
            $enddate = $req['date_end'];
            foreach($TravelEntryList as $Travelentry){

                    $key = $Travelentry->employee;

                    if($startdate >= $Travelentry->travel_date)
                    {
                        $firstdate = $startdate;
                    }
                    else
                        $firstdate = $Travelentry->travel_date;

                    if($enddate <= $Travelentry->return_date )
                    {
                        $lastdate = $enddate;
                    }
                    else
                        $lastdate = $Travelentry->return_date;

                    $holidays = $this->getholidays($firstdate,$lastdate);

                    $totalhours = $this->getWorkingDays($firstdate,$lastdate,$holidays);                    
                    $amount = $totalhours;  
    }

    private function getWorkingDays($FirstDate,$LastDate,$holidays){        

        $endDate = strtotime($LastDate); //Here i want to give only date not the time
        $startDate = strtotime($FirstDate); 

        $days = ($endDate - $startDate) / 86400 + 1;

        $no_full_weeks = floor($days / 7);
        $no_remaining_days = fmod($days, 7);    
    //Im doing even and odd saturday calculations....finally...

    $workinghours = $workingDays*9 +  $no_saturdays*7;  
        return $workinghours;
    }

Answer 1

这样的表达式可以提供所需的结果

echo strtotime('midnight', strtotime('2016-04-27 22:11')); // 1461715200
echo strtotime('2016-04-27'); // 1461715200

仅提取日期时间的日期以计算PHP中的总时间

1 个答案: