Question

我有这样的事情：

            service.getStuff()
            .map(...)
            .observeOn(AndroidSchedulers.mainThread())
            .retryWhen(errors -> errors.flatMap(t -> {
                return otherObservable.doOnNext(someSideEffect);
            }))
            .doOnCompleted(() ->  onComplete())
            .subscribe(onNext() , onError());

onNext()执行，onComplete()上的service.getStuff()来自doOnCompleted()

的原始观察点

问题：Observable.create(new Observable.OnSubscribe<InputStream>() { @Override public void call(final Subscriber<? super InputStream> subscriber) { call.enqueue(new Callback() { @Override public void onFailure(Call call, IOException e) { subscriber.onError(e); } @Override public void onResponse(Call call, Response response) throws IOException { subscriber.onNext(response.body().byteStream()); Log.d("HTTP", "calling complete"); subscriber.onCompleted(); Log.d("HTTP", "called complete"); } }); } }未执行。

原始的observable（service.getStuff）是：

{{1}}

Answer 1

我不完全理解发生了什么，但在找到this similar discussion后我没有使用flatMap重新实现它并且它有效：

.retryWhen(errors -> errors.zipWith(otherObservable, dummyZipFunction));

重试后没有调用doOnCompletedWhen

1 个答案: