重试后rxjava完成

时间:2019-02-25 08:52:32

标签: rx-java2 reactivex

我在Completeable上使用retryWhen运算符,有没有办法告诉它从重试Flowable中完成? 像这样-

PublishSubject<?> retrySubject = PublishSubject.create();
public void someFunction() {
    someCompletable.retryWhen(new Function<Flowable<Throwable>, Publisher<?>>() {
        @Override
        public Publisher<?> apply(Flowable<Throwable> throwableFlowable) throws Exception {
            return throwableFlowable.flatMap(throwable -> retrySubject.toFlowable(BackpressureStrategy.MISSING));
        }
    }).subscribe();
}

public void ignoreError(){
    retrySubject.onComplete();
}

1 个答案:

答案 0 :(得分:1)

您不能通过将flatMap设为空来停止它。同样,每个错误都会使越来越多的观察者订阅导致内存泄漏的主题。

使用takeUntil通过另一个来源停止序列:

PublishProcessor<Throwable> stopProcessor = PublishProcessor.create();

source.retryWhen(errors -> 
    errors.takeUntil(
        stopProcessor
    )
    .flatMap(error -> Flowable.timer(1, TimeUnit.SECONDS))
)

stopProcessor.onComplete();

编辑:如果要重复使用同一主题,可以在停止路径上取消显示项目:

PublishProcessor<Integer> stopProcessor = PublishProcessor.create();

source.retryWhen(errors -> 
    errors.takeUntil(
        stopProcessor.ignoreElements().toFlowable()
    )
    .flatMap(error -> stopProcessor)
)

// retry
stopProcessor.onNext(1);

// stop
stopProcessor.onComplete();