Question

在我的项目中，我使用SWRevealviewcontroller作为滑块菜单。当Project在后台时，然后Foreground那时我想要当前的前视图对象。

＆＃xA;＆＃xA;

如何从SWRevealviewcontroller获取当前的前视图控制器？

＆＃xA;＆＃xA;

   - （void）applicationWillEnterForeground：（UIApplication *）申请{＆＃xA;＆＃xA; SWRevealViewController * mainRevealController = [[SWRevealViewController alloc] init];＆＃xA;＆＃xA; NSLog（@“front：％@”，mainRevealController.frontViewController）;＆＃xA; }＆＃XA;

＆＃XA;

Answer 1

- (void)applicationDidBecomeActive:(UIApplication *)application 
{
    UIWindow *window=[UIApplication sharedApplication].keyWindow;
UIViewController *root = [window rootViewController];

UIStoryboard *storyboard = root.storyboard;
CustomViewController *vcc =(CustomViewController *) [storyboard instantiateViewControllerWithIdentifier:@"storyBoardID"];

[root presentModalViewController:vcc animated:YES];
}

当你的应用程序变为活动状态时，将ViewController传递给前端，此方法存在于appdelegate中

SWRevealViewController - 当前的Frontviewcontroller

1 个答案: