由可变地图

时间:2016-05-07 10:36:15

标签: kotlin

我有以下代码:

class Mapped(var data:Map<String,String>){
    val firstName:String by data
}

如果Mapped的使用方法如下,这样可以正常工作:

val mapped = Mapped(mapOf("firstName" to "initialFirstName"))
println(mapped.firstName); // prints "initialFirstName"

然而,由于data属性是可变的,我们可以改变它的值,即:

mapped.data = mapOf("firstName" to "updated");

firstName属性仍保留"initialFirstName"

是否解决了这个known/documented虽然出乎意料(对我而言)的行为?

1 个答案:

答案 0 :(得分:6)

在解决问题KT-5870KT-9772之前,您可以执行以下操作:

operator fun <V, V1 : V> (() -> Map<in String, V>).getValue(thisRef: Any?, property: KProperty<*>): V1 {
    val map = this()
    return map[property.name] as V1
}

然后可以按如下方式使用:

class Mapped(var data:Map<String,String>){
    val firstName:String by { data }
}

以上不能很好地处理可空性。这是一个改进的版本:

operator fun <V, V1 : V> (() -> Map<in String, V>).getValue(thisRef: Any?, property: KProperty<*>): V1 {
    val map = this()
    val key = property.name
    @Suppress("UNCHECKED_CAST")
    val value = map[key] as V1
    if (property.returnType.isMarkedNullable) {
        return value
    } else {
        if(value != null){
            return value
        }
        if(map.containsKey(key)){
            throw KotlinNullPointerException("Property baking map returned null value for key '$key' for non nullable property: $property")
        } else {
            throw KotlinNullPointerException("Property baking map has no key '$key' for non nullable property $property")
        }
    }
}