Question

这是我的名单dico：

dico <- list(list(list(c("dim.", "dimension", "dimensions", "mesures"
), c("45 cm", "45", "45 CM", "0.45m")), list(c("tamano", "volumen", 
"dimension", "talla"), c("45 cm", "45", "0.45 M", "45 centimiento"
)), list(c("measures", "dimension", "measurement"), c("45 cm", 
"0.45 m", "100 inches", "100 pouces"))), list(list(c("poids", 
"poid", "poids net"), c("100 grammes", "100 gr", "100")), list(
    c("peso", "carga", "peso especifico"), c("100 gramos", "100g", 
    "100", "100 g")), list(c("weight", "net wieght", "weight (grammes)"
), c("100 grams", "100", "100 g"))), list(list(c("Batterie oui/non", 
"batterie", "présence batterie"), c("Oui", "batterie", "OUI"
)), list(c("bateria", "bateria si or no", "bateria disponible"
), c("si", "bateria furnindo", "1")), list(c("Battery available", 
"battery", "battery yes or no"), c("yes", "Y", "Battery given"
))))

在视觉上看起来像：

[[1]]
[[1]][[1]]
[[1]][[1]][[1]]
[1] "dim."       "dimension"  "dimensions" "mesures"   

[[1]][[1]][[2]]
[1] "45 cm" "45"    "45 CM" "0.45m"


[[1]][[2]]
[[1]][[2]][[1]]
[1] "tamano"    "volumen"   "dimension" "talla"    

[[1]][[2]][[2]]
[1] "45 cm"          "45"             "0.45 M"         "45 centimiento"


[[1]][[3]]
[[1]][[3]][[1]]
[1] "measures"    "dimension"   "measurement"

[[1]][[3]][[2]]
[1] "45 cm"      "0.45 m"     "100 inches" "100 pouces"



[[2]]
[[2]][[1]]
[[2]][[1]][[1]]
[1] "poids"     "poid"      "poids net"

[[2]][[1]][[2]]
[1] "100 grammes" "100 gr"      "100"        


[[2]][[2]]
[[2]][[2]][[1]]
[1] "peso"            "carga"           "peso especifico"

[[2]][[2]][[2]]
[1] "100 gramos" "100g"       "100"        "100 g"     


[[2]][[3]]
[[2]][[3]][[1]]
[1] "weight"           "net wieght"       "weight (grammes)"

[[2]][[3]][[2]]
[1] "100 grams" "100"       "100 g" 
...

我希望获得列表中所有元素的所有长度。所以我想要一个看起来像这样的输出：

[[1]]
[[1]][[1]]
[[1]][[1]][[1]]
[1] 3   

[[1]][[1]][[2]]
[1] 4


[[1]][[2]]
[[1]][[2]][[1]]
[1] 4   

[[1]][[2]][[2]]
[1] 4


[[1]][[3]]
[[1]][[3]][[1]]
[1] 3

[[1]][[3]][[2]]
[1] 4



[[2]]
[[2]][[1]]
[[2]][[1]][[1]]
[1] 3

[[2]][[1]][[2]]
[1] 3      


[[2]][[2]]
[[2]][[2]][[1]]
[1] 3

[[2]][[2]][[2]]
[1] 4  


[[2]][[3]]
[[2]][[3]][[1]]
[1] 3

[[2]][[3]][[2]]
[1] 3
...

我知道我应该使用lapply，sapply和stuff，但是我被困了好几个小时。你会怎么做？

Answer 1

我们可以使用递归版lapply，即rapply

rl <- rapply(dico, length, how="list")
rl
#[[1]]
#[[1]][[1]]
#[[1]][[1]][[1]]
#[1] 4

#[[1]][[1]][[2]]
#[1] 4


#[[1]][[2]]
#[[1]][[2]][[1]]
#[1] 4

#[[1]][[2]][[2]]
#[1] 4
#---

获取R中列表列表元素的长度

1 个答案: