Question

我希望将下面的json字符串反序列化为3个不同的DataGrids。一个用于结果，一个用于提款，一个用于存款。有人有这么好的方法吗？任何帮助将非常感激。

{
  "results": [
    {
      "id": "51142254",
      "tp_id": "!XP4D49X0CD123628",
      "firstname": "Owner",
      "lastname": "Operator",
      "email": "",
      "phone": "",
      "enrolled": "1",
      "balance": 247.54,
      "fleet": "Test Express",
      "deposits": [
        {
          "id": "184022380",
          "date": "2016-02-17",
          "amount": "200.00",
          "transID": "135246",
          "memo": "Scheduled Deposit",
          "status": "Cleared"
        },
        {
          "id": "184022383",
          "date": "2016-02-25",
          "amount": "200.00",
          "transID": "246357",
          "memo": "Scheduled Deposit",
          "status": "Cleared"
        },
        {
          "id": "184022386",
          "date": "2016-03-02",
          "amount": "200.00",
          "transID": "975468",
          "memo": "Scheduled Deposit",
          "status": "Cleared"
        }
      ],
      "withdrawals": [
        {
          "id": "184026949",
          "date": "2016-03-09",
          "amount": "352.46",
          "transID": "395920",
          "memo": "Invoice\r\n\r\n100234",
          "status": "Cleared"
        }
      ]
    },
    {
      "id": "51142326",
      "tp_id": "!XP4D49X7CD123612",
      "firstname": "Owner",
      "lastname": "Operator",
      "email": "",
      "phone": "",
      "enrolled": "1",
      "balance": 0,
      "fleet": "Test\r\nExpress",
      "deposits": [],
      "withdrawals": []
    }
  ]
}

当我去json2chsarp.com时，这就是为我的课程生成的内容。我假设存款和取款部分没有显示，因为这里没有列出子节点。该如何正确完成？

public class Result
{
    public string id { get; set; }
    public string tp_id { get; set; }
    public string firstname { get; set; }
    public string lastname { get; set; }
    public string email { get; set; }
    public string phone { get; set; }
    public string enrolled { get; set; }
    public double balance { get; set; }
    public string fleet { get; set; }
    public List<object> deposits { get; set; }
    public List<object> withdrawals { get; set; }
}

public class RootObject
{
    public List<Result> results { get; set; }
}

Answer 1

您必须创建一个类Results并定义您的JSON具有的每个属性。此外，您还必须为存款和提款定义一个类，并在结果类中添加一个属性列表和列表< / strong>即可。然后你可以使用这个

var results = new JavaScriptSerializer().Deserialize<List<results>>();

希望这有帮助

在此之后，您可以使用对象填充数据网格

Answer 2

首先，我建议创建一个直接映射到Json字符串中给出的对象和属性的对象（以及后续的对象）。

然后您可以使用JsonConvert.DeserializeObject<T>("your json string here");其中T是您的新对象类型，将其转换回新对象的实例。

不要忘记在课堂上使用Newtonsoft.Json。

转到Newtonsoft's Website，看看如何做到这一点/如何运作。

我也会看一下another useful answer，并提出类似的问题。

希望这有帮助。

Answer 3

Newtonsoft JSON library是处理JSON对象的绝佳选择。使用JObject.Parse的动态功能，您可以在解析它之后从JSON对象中提取数据（其中rawJson是您的JSON字符串）：

    dynamic jsonBody = JObject.Parse(rawJson);
    dynamic results = jsonBody.results;

循环遍历结果数组，您可以获取插入数据网格所需的所有字段和数据：

    foreach(dynamic curResult in results)
    {
      JArray deposits = (JArray)curResult.deposits;
      JArray withdrawals = (JArray)curResult.withdrawals;

      //To get column names and values for your first data grid, iterate over the properties within curResult record
      JObject header = (JObject)curResult;
      var headerObjects = header.Properties().
          Find(x => 
              !x.Name.Equals("deposits") ||
              !x.Name.Equals("withdrawals"));
    }

您可以使用每个结果中的deposit数组和withdrawals数组中的记录来填充这些数据网格。

这只是此库允许您迭代JSON文档的众多方法之一。我希望这有用。

Answer 4

public class Deposite
{
    public int id { get; set; }
    public date date { get; set; }
    public double amount { get; set; }
    public int transID { get; set; }
    public string Memo { get; set; }
    public string status { get; set; }
}

public class Withdrawal
{
    public int id { get; set; }
    public date date { get; set; }
    public double amount { get; set; }
    public int transID { get; set; }
    public string Memo { get; set; }
    public string status { get; set; }
}

public class results
{
    public int id { get; set; }
    public int tp_id{ get; set; }
    public string firstname { get; set; }
    public string lastname { get; set; }
    public string email { get; set; }
    public string phone { get; set; }
    public string enrolled { get; set; }
    public string balance { get; set; }
    public string fleet { get; set; }
    public Deposite[] deposite { get; set; }
    public Withdrawal[] withdrawal { get; set; }
}

public class opt
{
    public results[] response { get; set; }
}

using System.Web.Script.Serialization;

JavaScriptSerializer objJS = new JavaScriptSerializer();
opt objopt  = new opt();
objopt  = objJS .Deserialize<opt >("Your String");

反序列化Json String .net

4 个答案: