我有一个需要反序列化为对象的JSON字符串。
这就是我的尝试:
班级:
public class trn
{
public string visited_date { get; set; }
public string party_code { get; set; }
public string response { get; set; }
public string response_type { get; set; }
public string time_stamp { get; set; }
public string trans_id { get; set; }
public double total_amount { get; set; }
public double discount { get; set; }
}
json string:
string json = "{\"trn\":{\"visited_date\":\"2015-04-05\",\"party_code\":\"8978a1bf-c88b-11e4-a815-00ff2dce0943\",\"response\":\"Reason 5\",\"response_type\":\"NoOrder\",\"time_stamp\":\"2015-04-05 18:27:42\",\"trans_id\":\"8e15f00b288a701e60a08f968a42a560\",\"total_amount\":0.0,\"discount\":0.0}}";
trn model2 = new System.Web.Script.Serialization.JavaScriptSerializer().Deserialize<trn>(json);
并使用json.net
trn model = JsonConvert.DeserializeObject<trn>(json);
但所有属性都使用空值初始化。
答案 0 :(得分:6)
您的JSON表示一个对象trn
作为另一个对象中的属性。所以你需要在代码中表示它。例如:
using System;
using System.IO;
using Newtonsoft.Json;
public class Transaction
{
[JsonProperty("visited_date")]
public DateTime VisitedDate { get; set; }
[JsonProperty("party_code")]
public string PartyCode { get; set; }
[JsonProperty("response")]
public string Response { get; set; }
[JsonProperty("response_type")]
public string ResponseType { get; set; }
[JsonProperty("time_stamp")]
public DateTime Timestamp { get; set; }
[JsonProperty("trans_id")]
public string TransactionId { get; set; }
[JsonProperty("total_amount")]
public double TotalAmount { get; set; }
[JsonProperty("discount")]
public double Discount { get; set; }
}
public class TransactionWrapper
{
[JsonProperty("trn")]
public Transaction Transaction { get; set; }
}
class Test
{
static void Main(string[] args)
{
string json = "{\"trn\":{\"visited_date\":\"2015-04-05\",\"party_code\":\"8978a1bf-c88b-11e4-a815-00ff2dce0943\",\"response\":\"Reason 5\",\"response_type\":\"NoOrder\",\"time_stamp\":\"2015-04-05 18:27:42\",\"trans_id\":\"8e15f00b288a701e60a08f968a42a560\",\"total_amount\":0.0,\"discount\":0.0}}";
var wrapper = JsonConvert.DeserializeObject<TransactionWrapper>(json);
Console.WriteLine(wrapper.Transaction.PartyCode);
}
}
请注意我是如何使用[JsonProperty]
属性来允许属性名称本身是.NET的惯用语,但仍然可以正确使用JSON属性名称。我还更改了Transaction
和VisitedDate
的类型。最后,total_amount
和discount
的值double
略微令人担忧 - 它们确实不适合货币值。不幸的是,你可能无法控制它。
答案 1 :(得分:1)
是的,正如@InvernoMuto所说,你的JSON字符串是一个具有嵌套对象属性的对象,内部对象是trn对象。您的JSON字符串需要像这样才能工作:
string json = "{\"visited_date\":\"2015-04-05\",\"party_code\":\"8978a1bf-c88b-11e4-a815-00ff2dce0943\",\"response\":\"Reason 5\",\"response_type\":\"NoOrder\",\"time_stamp\":\"2015-04-05 18:27:42\",\"trans_id\":\"8e15f00b288a701e60a08f968a42a560\",\"total_amount\":0.0,\"discount\":0.0}";
我认为乔恩的答案更为确定。
答案 2 :(得分:1)
您的JSON是Dictionary<string,trn>
,请尝试使用此Fiddle
using System;
using System.Collections.Generic;
using System.Linq;
using Newtonsoft.Json;
public class Program
{
public static void Main()
{
string json = "{\"trn\":{\"visited_date\":\"2015-04-05\",\"party_code\":\"8978a1bf-c88b-11e4-a815-00ff2dce0943\",\"response\":\"Reason 5\",\"response_type\":\"NoOrder\",\"time_stamp\":\"2015-04-05 18:27:42\",\"trans_id\":\"8e15f00b288a701e60a08f968a42a560\",\"total_amount\":0.0,\"discount\":0.0}}";
var p = JsonConvert.DeserializeObject<Dictionary<string,trn>>( json );
Console.WriteLine(p["trn"].party_code);
}
public class trn
{
public string visited_date { get; set; }
public string party_code { get; set; }
public string response { get; set; }
public string response_type { get; set; }
public string time_stamp { get; set; }
public string trans_id { get; set; }
public double total_amount { get; set; }
public double discount { get; set; }
}
}