Question

我正在尝试开发一个简单的高低游戏，如果他们想再玩一下，在玩游戏后会询问用户。如果我删除外部while循环，内部循环的逻辑正是我想要它做的，但是我不确定如何用一个外部循环来包装内部循环，这将再次询问游戏问题，如果答案是肯定的话他们回到内循环。以下是我的代码。

import java.util.Scanner;
import java.util.Random;

public class HiLoGuess {

    public static void main(String[] args) {

        Scanner scan = new Scanner (System.in); // Creates scanner object.
        Random numb = new Random();             // Creates an instance of the random class.
        int guess = -1;                         // Placeholder for users guess.
        int answer = numb.nextInt(100)+1;       // Generates a random number for the game.
        int count = 0;                          // Placeholder for the guess counter.
        int sentinel = 0;                       // Placeholder for players answer as to whether they want to play again or not.
        String newgame = "y";

        while (newgame.equalsIgnoreCase("y"))
        {
            while (guess != sentinel && guess != answer)                //Loop that ends when user enters a zero.
            {
                System.out.println ("Enter a number between 1-100 or 0 to quit");
                guess = scan.nextInt();
                count++;

                if (guess < answer && guess > 0 )
                {
                    System.out.println("Your guess is too low, guess again");
                }
                else if (guess > answer)
                {
                    System.out.println ("Your guess is to high, guess again");
                }

                else if (guess == answer)
                {
                    System.out.println ();
                    System.out.println ("You guessed correctly, you win!!!");
                    System.out.println ("It took you " + count + " guesses");
                }
            }
            System.out.print();
            System.out.println("Play another game: y or n?");
            newgame = scan.nextLine();
        }
    }
}

Answer 1

您需要将这些初始化放入外部循环中：

int guess = -1;
int answer = numb.nextInt(100)+1;
int count = 0;

否则他们保留上一场比赛的值，内圈不再被执行。

Answer 2

你永远不会重置你的猜测，哨兵或回答变量

so（guess！= sentinel＆amp;＆amp; guess！= answer）在第一次玩游戏后总是评估为false，因此内部while循环在第一次游戏后永远不会执行

 while (guess != sentinel && guess != answer) //this is false after the first game because you don't reset variables
            { ...}

OP评论更新： 让你的代码做你想要的你需要在outter和inner while循环之间添加重置像这样

           while (newgame.equalsIgnoreCase("y"))
            {
            guess = -1;                  
            answer = numb.nextInt(100)+1;
            count = 0;
            while (guess != sentinel && guess != answer)                //Loop that ends when user enters a zero.
                { ...}
}

Answer 3

替换newgame = scan.nextLine（）;通过这个：newgame = scan.next（）;

您需要在while循环中初始化变量，以便将标志重置为false并随机生成新结果以进行猜测。

Return

似乎无法重复我的低 - 高游戏

3 个答案: