Question

在以下代码中，我使用netmq push / pull套接字发送和接收100000条消息。我首先尝试在我的拉套接字上使用ReceiveFrameString（ReceiveSimple方法）进行简单的阻塞调用，然后我尝试使用轮询器来执行相同的操作（ReceiveWithPoller方法）。

使用轮询器会对发送/接收邮件所花费的时间产生重大影响。我试图找出为什么我自己使用dotTrace，我发现花了很多时间等待Socket.Select执行。

有人可以证实或解释这种差异吗？

using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using NetMQ;
using NetMQ.Sockets;

namespace PushPull
{
    class Program
    {
        static int messageReceived = 0;

        const int sampleCount = 100 * 1000;

        static void Main(string[] args)
        {
            // Create psu socket
            PushSocket pushSocket = new PushSocket();
            pushSocket.Bind("tcp://localhost:5555");

            // Create pull socket
            PullSocket pullSocket = new PullSocket();
            pullSocket.Connect("tcp://localhost:5555");

            Console.WriteLine("Ready...press any key to start");
            Console.ReadKey();
            Console.WriteLine();

            // Start sending
            Task.Run(() =>
            {
                for (int i = 0; i < sampleCount; i++)
                {
                    pushSocket.SendFrame(Encoding.UTF8.GetBytes("ping"));
                }
            });

            Stopwatch sw = Stopwatch.StartNew();

            //ReceiveSimple(pullSocket);

            ReceiveWithPoller(pullSocket);

            // Display result.
            sw.Stop();
            Console.WriteLine();
            Console.WriteLine("{0} message exchanged in {1} msecs", sampleCount, sw.Elapsed.TotalMilliseconds);
        }

        private static void ReceiveSimple(PullSocket pullSocket)
        {
            messageReceived = 0;
            do
            {
                pullSocket.ReceiveFrameString();
            } while (!HandleMessage());
        }

        private static void ReceiveWithPoller(PullSocket pullSocket)
        {
            NetMQPoller poller = new NetMQPoller();
            poller.Add(pullSocket);
            pullSocket.ReceiveReady += (sender, eventArgs) =>
            {
                if (HandleMessage())
                {
                    poller.Stop();
                }
            };
            poller.Run();
        }

        private static bool HandleMessage()
        {
            messageReceived++;

            if (messageReceived % 10000 == 0)
            {
                Console.WriteLine("10k");
            }

            return messageReceived == sampleCount;
        }
    }
}

Answer 1

当您处理大量消息时，Poller很昂贵，但有一个非常简单的解决方案。

在收到ready事件时获取队列中的所有消息，您可以使用Try *方法获取，例如：

 pullSocket.ReceiveReady += (sender, eventArgs) =>
 {
    string message;
    while (pullSocket.TryReceiveFrameString(out message) 
    {
        if (HandleMessage())
        {
            poller.Stop();
        }
    }
 };

使用netmq poller对性能的影响

1 个答案: