Question

我在iOS中解析JSON文件，我在tableview中获取元素，但是当我创建（prepareForSegue）获取tableview元素时，我无法获取图像，我收到此错误：

无法识别的选择器发送到实例0x7fa3427c5b20 2016-05-05 05：08：43.287 MovieClub [4845：212195] ***由于未捕获的异常'NSInvalidArgumentException'终止应用程序，原因：' - [__ NSCFString size]：无法识别的选择器已发送例如0x7fa3427c5b20'

在这行代码中：

self.postt.image =[self.actuatlitDetail objectForKey:@"poster_240x342"];

Answer 1

如果[self.actuatlitDetail objectForKey:@"poster_240x342"]返回NSURL，您可以使用

NSURL *imageURL = [self.actuatlitDetail objectForKey:@"poster_240x342"];
self.postt.image = [UIImage imageWithData:[NSData dataWithContentsOfURL:imageURL]];

如果是NSString则表示URL

NSString *imageURLString = [self.actuatlitDetail objectForKey:@"poster_240x342"];
self.postt.image = [UIImage imageWithData:[NSData dataWithContentsOfURL:[NSURL URLWithString:imageURLString]]];

您可以在后台加载图片

__weak typeof(self) weakSelf = self;
dispatch_queue_t aQueue = dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0);
dispatch_async(aQueue, ^{
    NSURL *imageURL = [weakSelf.actuatlitDetail objectForKey:@"poster_240x342"];
    UIImage *image = [UIImage imageWithData:[NSData dataWithContentsOfURL:imageURL]];
    dispatch_async(dispatch_get_main_queue(), ^{
        weakSelf.postt.image = image;
    });
});

Answer 2

它的urt值为actuatlitDetail，得到以下代码，

NSString *imageurl = [self.actuatlitDetail objectForKey:@"poster_240x342"];
NSString *encodedUrlString = [imageurl stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *imageURL = [NSURL URLWithString: encodedUrlString];
NSData *imageData = [NSData dataWithContentsOfURL:imageURL];
UIImage *imag = [UIImage imageWithData:imageData];
self.postt.image = imag;

希望它有用

Answer 3

设置图像路径然后按照：

NSData * imageData = [[NSData alloc] initWithContentsOfURL: [NSURL URLWithString: @"Your image url string"]];
UIImageView *imView = [[UIImageView alloc] initWithImage:[UIImage imageWithData: imageData]];

从我的字典中获取图像会导致“无法识别的选择器”错误

3 个答案: