Question

我正在访问地址簿联系人，然后在所有联系人上运行for循环。循环的主要目的是访问用户地址簿联系人的名字和电话号码值，并将这些值放入NSString对象。

以上所有方法都很完美。我的问题是，如果电话号码数据包含此字符串，我需要执行特定代码：_$!<Mobile>!$_

因此，我在包含电话号码数据的对象上设置了rangeOfString方法调用，这会导致问题。

在我将rangeOfString方法调用添加到我的代码后，这是打印到控制台的内容：

2014-01-18 12:10:49.190 PhotoTest1[1244:60b] -[__NSCFType rangeOfString:]: unrecognized     selector sent to instance 0x14e9ac90
2014-01-18 12:10:49.193 PhotoTest1[1244:60b] *** Terminating app due to uncaught exception     'NSInvalidArgumentException', reason: '-[__NSCFType rangeOfString:]: unrecognized selector    sent to instance 0x14e9ac90'
*** First throw call stack:
(0x2f8f6f4b 0x39d376af 0x2f8fa8e7 0x2f8f91cb 0x2f8fa478 0x55e29 0x3206e37b 0x3206e139     0x32117e27 0x3215449b 0x32152dd3 0x32151e25 0x3232dcb3 0x3209e713 0x3209e6b3 0x3209e691    0x3208a11f 0x3209e107 0x3209ddd9 0x32098e65 0x3206e79d 0x3206cfa3 0x2f8c2183 0x2f8c1653 0x2f8bfe47 0x2f82ac27 0x2f82aa0b 0x34551283 0x320ce049 0x54495 0x3a23fab7)
libc++abi.dylib: terminating with uncaught exception of type NSException

这是我的所有代码都以for循环开头。一旦到达“if([phoneNumber rangeOfString:@"+"].location == NSNotFound)”：

，错误就会打印到控制台

for (i = 0; i < [allContacts count]; i++)
    {


        Person *person = [[Person alloc] init];

        ABRecordRef contactPerson = (__bridge ABRecordRef)allContacts[i];
        NSString *firstName = (__bridge_transfer NSString
                                *)ABRecordCopyValue(contactPerson, kABPersonFirstNameProperty);
        NSString *phoneNumber = (__bridge_transfer NSString *)ABRecordCopyValue(contactPerson, kABPersonPhoneProperty);


        person.firstName = firstName;

        person.phoneNumber = phoneNumber;

        NSLog(@"%@", phoneNumber);

        //MOBILE PHONE PSEUDOCODE STARTS HERE

        // If the value of phoneNumber contains the text “_$!<Mobile>!$_” , then we want to grab a substring out of it.

        if([phoneNumber rangeOfString:@"_$!<Mobile>!$_"].location == NSNotFound) {

            NSLog(@"Not a mobile phone number");

        } else {

            NSLog(@"It is a mobile phone number");

            // If the value of phoneNumber contains a “+”, then grab the substring that starts with the + and then the next additional 10 spaces and place the substring in the mobilePhoneNumber object. (Which will grab the + sign and the 10 digit phone number. )

            if([phoneNumber rangeOfString:@"+"].location == NSNotFound) {


                NSLog(@"Phone number does not start with a +");


            } else {

                NSLog(@"Phone number does start with a +");

                NSString *subString = [phoneNumber substringWithRange: NSMakeRange(0, [phoneNumber rangeOfString: @"+"].location)];

                NSLog(@"%@", subString);

            }

        }

        //PFQUERY CODE TESTING!!!

}   
}

}

感谢您的帮助。

Answer 1

电话号码不是字符串。它定义为多变量，因为那里可以有0..x数字。

你不能只把它当作一个字符串。你需要枚举多元\

e.g。获得任何类型的第一个

    ABMultiValueRef phoneEntries = ABRecordCopyValue(person, kABPersonPhoneProperty);       
    NSMutableArray *numbers = [NSMutableArray array)];
    for(int i = 0; i < ABMultiValueGetCount(phoneEntries); i++) {
         NSString *number = (__bridge_transfer NSString*)ABMultiValueCopyValueAtIndex(phoneEntries, i))];
         // Do what you want with the number
         [numbers addObject:number];
    }
    CFRelease(phoneEntries);

rangeOfString方法调用导致无法识别的选择器错误

1 个答案: