Question

所以看一下：我在游戏中有一个怪物，当玩家与他发生碰撞时，会出现一个面板并说再试一次。现在有一个盾牌对象，可以保护玩家免于死亡，所以当玩家与它发生碰撞然后如果你触摸怪物你不应该死一次：就像那样，你触摸盾牌和你免受一人死亡。你能帮我写这段代码吗？

public GameObject panel;
public bool hasShield = false; /* no shield in the beginning */    

void OnCollisionEnter(Collision col)
{
    if(col.gameObject.tag == "Shield") 
    {
        hasShield = true; //We are safe now.
        /* TODO: StartCoroutine() or Invoke() to reset the variable and the graphic effect after some amount of time. */
    }
    else if (col.gameObject.tag == "Monster" && !hasShield) 
    { 
        //We hit a monster and had no shield. Display gameover.
        panel.SetActive (true);
    }
    //I assume the panel is inactive by default so no need to call SetActive(false) on it.
}

Answer 1

永远无法访问此代码的内部：

     if (col.gameObject.tag == "Shield") 
    {
        if(col.gameObject.tag == "Monster")
        {
            panel.SetActive(false);
        }
    }

对于要通过的第一个if检查，标记必须为“Shield”，但是对于要通过的第二个测试，它必须是“Monster”。这两个条件不能同时为真，代码相当于

 if(col.gameObject.tag == "Shield" && col.gameObject.tag == "Monster")

但是，如果您在上面的表达式中将&&替换为||（逻辑或），您将获得所需的结果。所以，重写的代码将是

    if (col.gameObject.tag == "Monster") 
    { 
        panel.SetActive (true);
    }
    if (col.gameObject.tag == "Shield" || col.gameObject.tag == "Monster") 
    {
         panel.SetActive(false);
    }

如果是“盾牌”或“怪物”，内部代码现在会触发。

编辑：正如我们在评论中谈到的那样，逻辑总体上存在缺陷。现在根据你的描述

我触摸怪物后需要激活面板，但是如果我触摸盾牌然后触摸怪物那么面板就不应该出现了

我建议如下：收集盾牌后，将其保存到某个变量，例如

bool hasShield;

收集盾牌时将其设为true。然后，如果你击中某个东西，检查它是否是一个怪物，如果你没有盾牌，那么你会看到“游戏结束”屏幕。所以玩家应该看起来像

    public GameObject panel;
    public bool hasShield = false; /* no shield in the beginning */    

    void OnCollisionEnter(Collision col)
    {
        if(col.gameObject.tag == "Shield") 
        {
             hasShield = true; //We are safe now.
             /* TODO: StartCoroutine() or Invoke() to reset the variable and the graphic effect after some amount of time. */
        }
        else if (col.gameObject.tag == "Monster") 
        { 
            if(!hasShield)
                panel.SetActive (true);  //We hit a monster and had no shield. Display gameover.

            else
                hasShield = false; //loose the shield
        }
        //I assume the panel is inactive by default so no need to call SetActive(false) on it.
    }

Answer 2

这是核心代码！

        Please use onchange event instead of onclick and pass the value in the ValueID function.

        Please replace javascript and php code with this:

            <script>
     function ValueID(vid){
        $.ajax({
                    url: 'select_modelcar.php?brandid='+vid,              
                    type: 'POST',
                    success: function (data) {
                        if (data === 'success') {
                           document.getElementById("getval").innerHTML = data;
                        }
                    }

                });  

     };
    </script>

                <select name="select_brandcar" id="select_brandcar" onchange="ValueID(this.value);" >
                <option>Press Choose</option>
                <?php 
                $sql = sprintf ("SELECT * FROM brand" );
                $res = mysql_query ($sql);
                while ($arr = mysql_fetch_array($res)){
                   printf ("<option value='%s'>%s</option>" ,$arr['id'], $arr['name']);
                 }
               ?>
            <span id="getval"></span>


In PHP FIle:
<?php
mysql_query("SET NAMES UTF8");
include 'include_connectdb.php';
@$varbrandid = $_GET['brandid'];
@$sql = sprintf("SELECT * FROM maingeneration WHERE brandfk = %s", $varbrandid);
/*id ของตาราง catagory*/
@$res = mysql_query($sql);
$select = "<select name='select' id='select'>");
while ($arr = mysql_fetch_array($res)) {
    $select .= printf("<option value='%s'>%s</option>", $arr['maingenerationid'], $arr['maingenerationname']);
}
$select .="</select>";
echo $select;
exit;
?>

涂鸦跳团结c＃

2 个答案: