Question

我想获得DocID

的开始时间重叠计数

在下面的例子中，9：00-9：15重叠在9：00-9：30 所以我希望DocID（111）的计数为2

=============================================================
EncID   |  Pid   |  DocID  |  Date     | StartTime | EndTime|
=============================================================
1       |  11    |  111    | 25/3/2016 | 9:00      | 9:30   |    
2       |  12    |  111    | 25/3/2016 | 9:00      | 9:15   |    
3       |  13    |  111    | 26/3/2016 | 10:00     | 10:30  |    
=============================================================





Expected Out put
==============
DocID | count|
==============
111   |  2   |
==============

Answer 1

这样的事情应该有效并避免OR。子查询应该有效运行。

SELECT 
    T1.DocID,
    (
        SELECT COUNT(*)
        FROM [Table] T2
        WHERE T1.DocID = T2.DocID
            AND T1.[Date] = T2.[Date]
            AND T1.StartTime <= T2.EndTime
            AND T1.EndTime >= T2.StartTime
    ) AS [Count]
FROM [Table] T1
GROUP BY
    T1.DocID

如果您还希望过滤以仅显示重叠的记录，则最好将子查询转换为连接（不是更高效，但绝对更容易过滤）：< / p>

SELECT 
    T1.DocID,
    COUNT(*) AS [Count]
FROM [Table] T1
    INNER JOIN [Table] T2
        ON T1.DocID = T2.DocID
            AND T1.[Date] = T2.[Date]
            AND T1.StartTime <= T2.EndTime
            AND T1.EndTime >= T1.EndTime
GROUP BY
    T1.DocID
HAVING
    COUNT(*) > 1

如何在MSSQL中找到时间重叠

1 个答案: