Question

option1 = ['cherry','lemon','orange','plum','bell','bar','7']
option2 = ['cherry','lemon','orange','plum','bell','bar','7']
option3 = ['cherry','lemon','orange','plum','bell','bar','7']

 count = 0
while True:

game = str(input('if you want to start a game press y, if you want to back    out press n\n'))
if game == 'y':
    result1 = print(random.sample(option1,1))
    result2 = print(random.sample(option2,1))
    result3 = print(random.sample(option3,1))
    playercoin = open('playercoin.txt','w')
    coin = 10 - count - 1
    print(coin, file=playercoin)
    playercoin.close()

    machinecoin = open('machinecoin.txt','w')
    count = count +1
    print(slotcoins + count, file=machinecoin)
    machinecoin.close()
if result1 == 'cherry':
    playercoin = open('playercoin.txt','w')
    cherrywin = coins + 2
    print(coins, file=playercoin)
    playercoin.close()
    print('you have won 2 coins')

我正在尝试创建一个运行老虎机的程序，但是我无法让程序在result1获取项目cherry时识别。它只是继续循环。

Answer 1

这样的事情：

game = str(input('if you want to start a game press y, if you want to back    out press n\n'))
if game == 'y':
    # Since you are after one value i.e. cherry why not use choice function
    result1 = random.choice(option1)
    result2 = random.choice(option2)
    result3 = random.choice(option3)
    print([result1, result2, result3])  # You can print them all together

    # Or use sample to get all 3 results at once
    options = ['cherry', 'lemon', 'orange', 'plum', 'bell', 'bar', '7']
    results = random.sample(options, 3)
    print(results)
    print(results[0])  # will print result1

我的程序问题（Python 3.5）

1 个答案: