Question

这是我的程序

    import time
    print('hello, i am the consonants finder and i am going to find he consonants in your word')
    consonants = 'b'  'c' 'd' 'f' 'g' 'h' 'j' 'k' 'l' 'm' 'n' 'p' 'q' 'r' 's' 't' 'v' 'w' 'x' 'y' 'z'
    word = input('what is your word: ').lower()
    time.sleep(1)
    print('here is your word/s only in consonants')
    time.sleep(1)
    print('Calculating')
    time.sleep(1)

    for i in word:
        if i == consonants:
            print((i), ' is a consonant')

这是输出：

hello, i am the consonants finder and i am going to find he consonants in your word
what is your word: hello
here is your word/s only in consonants
Calculating
        #No output

输出怎么不给辅音

这是输出应该是什么：

 hello, i am the consonants finder and i am going to find he consonants in your word
what is your word: hello
here is your word/s only in consonants
Calculating
hll

Answer 1

你可以用列表理解来做到这一点：

print ''.join([c for c in word if c in consonants])

虽然这会删除所有点，冒号，逗号，但也不会考虑重音字母。

我宁愿删除元音：

word = "hello again, consider CAPS"
vocals = 'aeiou'
print ''.join([c for c in word if c.lower() not in vocals])

Answer 2

from time import sleep

CONSONANTS = set('bcdfghjklmnpqrstvwxyz')

print('hello, i am the consonants finder and i am going to find the consonants in your word')

word = input('what is your word: ').lower()
sleep(1)

print('Here is your word/s only in consonants:')
print("".join(ch for ch in word if ch in CONSONANTS))

你的错误：

consonants = 'b'  'c' 'd'    # ?

当你有像这样的字符串运行时，Python将它们组合成一个字符串;所以你有效地写了consonants = 'bcdfghjklmnpqrstvwxyz'（一个字符串）。

然后

if i == consonants:

i是一个字符，consonants是所有辅音;他们将从不匹配。因此，您获得没有字符！

你可以用if i in consonants:替换它，它会起作用;但是制作辅音会更快。（ch in str必须扫描字符串，一次扫描一个字符; ch in set只执行一次操作。

Answer 3

将您的代码更改为：

for i in word:
if i in consonants:
    print(i,end="")

Answer 4

import time
print('hello, i am the consonants finder and i am going to find he consonants in your word')
consonants = 'bcdfghjklmnpqrstvwxyz'
word = input('what is your word: ').lower()
time.sleep(1)
print('here is your word/s only in consonants')
time.sleep(1)
print('Calculating')
time.sleep(1)

for i in word:
    if i in consonants:
        print((i), ' is a consonant')

就像你在＆＃34; i in word＆＃34;部分以同样的方式做辅音部分。将辅音变量视为包含所有辅音的字符串。所以现在你只是检查单词中的每个字母是否都包含在辅音变量中（这是一个包含所有辅音的字符串）。

否则， Hugh Bothwell 正确指出你做错了什么

干杯!!!

在一个单词中查找和删除元音：我的程序不提供辅音

4 个答案: