Question

我正在尝试创建一个pygame程序，以查看用户是否单击了一个矩形，如果是，则更改该矩形的颜色。

这是我绘制屏幕的初始代码：

import pygame
import sys

pygame.init()

size_x = 650
size_y = 550
bkg_colour = 0, 0, 0
white = 255, 255, 255
colour = 0, 130, 90
position_x, position_y = 70, 100
screen = pygame.display.set_mode((size_x, size_y))

while True:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            sys.exit()

        screen.fill(bkg_colour)

        for x in range(-50, 500, position_x + 20):
            for y in range(-50, 400, position_y + 20):
                pygame.draw.rect(screen, colour, (position_x + x, position_y + y, position_x, position_y), 0)

        pygame.display.flip()

我尝试做的是像这样使用pygame.Rect和collisionpoint：

for x in range(-50, 500, position_x + 20):
            for y in range(-50, 400, position_y + 20):
                rect_size = pygame.Rect(position_x + x, position_y + y, position_x, position_y)
                pygame.draw.rect(screen, colour, rect_size, 0)

if event.type == pygame.MOUSEBUTTONDOWN:
            click = rect_size.collidepoint(pygame.mouse.get_pos())

            if click == 1:
                print("Clicked")
                pygame.draw.rect(screen, white, rect_size, 0)

pygame.display.flip()

但它的作用只适用于屏幕上最后绘制的矩形。如何使其适用于屏幕上的每个矩形？

Answer 1

rect_size一次保存一个值，并一次又一次地覆盖它，直到它保存最后一个矩形。

你想要保存一个矩形列表并检查所有矩形的碰撞。

而不是

rect_size = pygame.Rect(position_x + x, position_y + y, position_x, position_y)

你想做点什么：

rect_sizes.append(pygame.Rect(position_x + x, position_y + y, position_x, position_y))

然后迭代rect_sizes并检查每个碰撞。

rect_sizes = []
for x in range(-50, 500, position_x + 20):
    for y in range(-50, 400, position_y + 20):
        rect_size = pygame.Rect(position_x + x, position_y + y, position_x, position_y)
        pygame.draw.rect(screen, colour, rect_size, 0)
        rect_sizes.append(rect_size)

if event.type == pygame.MOUSEBUTTONDOWN:
    for rect_size in rect_sizes:
        click = rect_size.collidepoint(pygame.mouse.get_pos())

        if click == 1:
            print("Clicked")
            pygame.draw.rect(screen, white, rect_size, 0)

如何检查鼠标点击是否在此pygame程序中的每个矩形的矩形内？

1 个答案: