Question

为什么这个有效：

lis = [8, 5, 6]
   def fun():
       for i in lis:
          print i
       for i in lis:
          print i
fun()

而这个不是在使用csv文件的时候：

def miladifromhijri(intinp1):#, inp2, intinp3):
    fulyear = intinp1 - 1
for row in majmouaread:
        introw = int(row[0])
        if introw <= fulyear:
            years = []
            years.append(introw)
            near = years[::-1][0]
            nearlessyear = near
for row in majmouaread:#this one doesn't get executed
    print row

我想使用第二个循环使用nearlessyear变量，因为如果我继续在第一个循环中变量没有得到常量，它会继续使用在下一步中没用的数据。

Answer 1

我猜你正在寻找休息声明。如果找到了您要查找的值，只需退出循环：

def miladifromhijri(intinp1):#, inp2, intinp3):
    fulyear = intinp1 - 1
nearlessyear = 0
for row in majmouaread:
        introw = int(row[0])
        if introw <= fulyear:
            years = []
            years.append(introw)
            near = years[::-1][0]
            nearlessyear = near
            break
for row in majmouaread:#this one doesn't get executed
    print row

python2第二个循环里面的函数* pycharm

1 个答案: