Question

QUERY：

select ws_path from workpaths where 
(
   (ws_path like '%R_%') or
   (ws_path like '%PB_%' ) or
   (ws_path like '%ST_%')
)

输出：

/x/eng/users/ST_3609843_ijti4689_3609843_1601272247
/x/eng/users/ST_3610020_zozt5229_3610020_1601282033
/x/eng/users/ST_3611181_zozt5229_3611181_1601282032
/x/eng/users/ST_3611226_zozt5229_3611226_1601282033
/x/eng/users-random/john/N_3582168_3551186_1601040805
/x/eng/users-random/james/N_3582619_3551186_1601041405
/x/eng/users-random/jimmy/N_3582791_3551186_1601042005
/x/eng/users/R_3606462_3606462_1601251334
/x/eng/users/R_3611775_3612090_1601290909
/x/eng/users/R_3612813_3613016_1601292252

是否可以通过ST_，N_和R_进行部分分组？
即group by ws_path因为明显的原因而暂时无法工作

我只需要查看路径中的最后一项（用'/'分隔），然后用'_'分割前面的部分

Answer 1

您可以使用regexp_substr来搜索要搜索的模式，然后使用group by这些事件的数量。

select regexp_substr(ws_path,'\/R_|\/PB_|\/ST_'), count(*) 
from workpaths 
group by regexp_substr(ws_path,'\/R_|\/PB_|\/ST_')

Answer 2

Regexp是一个很好的解决方案，但价格昂贵。更简单的子字符串可能更便宜，更快：

CREATE TABLE tbl (field1 VARCHAR(100));

INSERT INTO dbo.tbl
        ( field1 )
VALUES  
('/x/eng/users/ST_3609843_ijti4689_3609843_1601272247'),
('/x/eng/users/ST_3610020_zozt5229_3610020_1601282033'),
('/x/eng/users/ST_3611181_zozt5229_3611181_1601282032'),
('/x/eng/users/ST_3611226_zozt5229_3611226_1601282033'),
('/x/eng/users-random/john/N_3582168_3551186_1601040805'),
('/x/eng/users-random/james/N_3582619_3551186_1601041405'),
('/x/eng/users-random/jimmy/N_3582791_3551186_1601042005'),
('/x/eng/users/R_3606462_3606462_1601251334'),
('/x/eng/users/R_3611775_3612090_1601290909'),
('/x/eng/users/R_3612813_3613016_1601292252');

SELECT
    COUNT(CASE WHEN field1 LIKE '%/ST_%' THEN 1 ELSE NULL END) AS 'st_count',
    COUNT(CASE WHEN field1 LIKE '%/N_%' THEN 1 ELSE NULL END) AS 'n_count',
    COUNT(CASE WHEN field1 LIKE '%/R_%' THEN 1 ELSE NULL END) AS 'r_count'
FROM dbo.tbl

部分群体

2 个答案: