Question

我如何编写代码，将9个人的列表尽可能均匀地分成2辆车，但是他们会在python中随机放入每辆车？基本上我正在寻找类似于此的回报：
车1：人8，人2，人4，人7 车2：Person5，Person1，Person3，Person6，Person9

Answer 1

只需将整个列表洗牌，然后将该列表分成两个夹头，一个包含4个人，另一个包含其余的：

import random

people = ['foo', 'bar', 'baz', 'eggs', 'ham', 'spam', 'eric', 'john', 'terry']
random.shuffle(people)
car1, car2 = people[:4], people[4:]

如果您无法直接对人员列表进行排序，请改为使用random.sample()：

people = ['foo', 'bar', 'baz', 'eggs', 'ham', 'spam', 'eric', 'john', 'terry']
shuffled = random.sample(people, len(people))
car1, car2 = shuffled[:4], shuffled[4:]

后一种方法的演示：

>>> import random
>>> people = ['foo', 'bar', 'baz', 'eggs', 'ham', 'spam', 'eric', 'john', 'terry']
>>> shuffled = random.sample(people, len(people))
>>> shuffled[:4], shuffled[4:]
(['bar', 'baz', 'terry', 'ham'], ['spam', 'eric', 'foo', 'john', 'eggs'])

Answer 2

from random import shuffle
x = [i for i in range(10)]
shuffle(x)
print x
mid = int(len(x)/2)
car1 = x[:mid]
car2 = x[mid:]
print car1
print car2

从python中的列表返回两个随机选择的组

2 个答案: