MiniZinc - 多个设施的任务调度 - 累积＆＃39; var opt错误＆＃39;

Question

我是MiniZinc的新手，我在执行以下CP配方时遇到问题（可以找到问题的完整表述here (page 4/16)）

我的实现看起来像下面的代码，但我在跟踪错误时遇到了困难：MiniZinc: type error: no function or predicate with this signature found: 'comulative(array[int] of var opt int,array[int] of var opt int,array[int] of var opt int,int)'。

这是因为数组理解受某些var影响，在本例中为变量x。

您对如何使cumulative约束使用选项变量或任何可能的解决方法有任何建议吗？

先谢谢你的帮助： - ）

include "cumulative.mzn";
include "element.mzn";

int: numJ; % number of tasks
int: numI; % number of facilities

% Tasks
set of int: Tasks = 1..numJ;

% Facilities
set of int: Facilities = 1..numI;

% Max consumptions of facilities
array[Facilities] of int: C;

array[Tasks] of int: d; % due times
array[Tasks] of int: r; % release times
array[Facilities, Tasks] of int: c; % c[i,j] = consumption of task j at facility i
array[Facilities, Tasks] of int: p; % p[i,j] = processing time of task i at facility j
array[Facilities, Tasks] of int: F; % F[i,j] = fixed cost paid when task j is assigned to facility i

% start time's domain is an interval <0, maximum of due times>
array[Tasks] of var 0..max(d): s;

% assign task to a facility
% x[3] = 1 --> task 3 is assigned to facility 1
array[Tasks] of var 1..numI: x;

% something like a temporary processing time
% im not really sure about this
array[Tasks] of var 0..max(p): u;

constraint forall(j in Tasks)(
  element(
    x[j],
    [p[i,j] | i in Facilities],
    u[j]
  )
);


constraint forall(i in Facilities)(
  comulative(
    [s[j] | j in Tasks where x[j] == i],
    [p[i,j] | j in Tasks where x[j] == i],
    [c[i,j] | j in Tasks where x[j] == i],
    C[i]
  )
);




% A task cant start before its release time
constraint forall(j in Tasks)(s[j] >= r[j]);
% A task cant run longer than its due time
constraint forall(j in Tasks)(s[j] <= d[j] - u[j]);

% Minimize total cost
solve minimize sum(j in Tasks)(F[x[j],j]);

output [ "start: ", "\n", show(s), "\n", "facility: ", "\n" , show(x) , "\n"];

简单数据集：

C = [8, 8, 6, 5];

numJ = 12;
numI = 4;
r = [0, 1, 2, 0, 1, 2, 0, 1, 2, 0, 1, 2];

d = [1, 2, 3, 1, 2, 3, 1, 2, 3, 1, 2, 3];

c = [|8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, |8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, 8, |6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, 6, |5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, 5, |];

p = [|1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, |1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, |1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, |1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, |];

F = [|0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 1, 1, |1, 1, 1, 0, 0, 0, 1, 1, 1, 1, 1, 1, |1, 1, 1, 1, 1, 1, 0, 0, 0, 1, 1, 1, |1, 1, 1, 1, 1, 1, 1, 1, 1, 0, 0, 0, |];

Answer 1

即使你提到你找到了解决方案，但这里有一个使用累积的版本（＆＃34; cumulative_opt.mzn＆＃34;中的选择版本）。

include "globals.mzn"; % includes the file "cumulative_opt.mzn"
% ....

constraint forall(i in Facilities)(
    cumulative(
    % [s[j] | j in Tasks where x[j] == i], % original
    % [p[i,j] | j in Tasks where x[j] == i], % original
    % [c[i,j] | j in Tasks where x[j] == i], % original

    [s[j] | j in Tasks where x[j] == i],
    [p[i,j] | j in Tasks], % <-- no condition clause here
    [c[i,j] | j in Tasks], % <-- no condition clause here
    C[i]
 )
);

Answer 2

我提出了这个解决方案，我希望它比具有累积约束的解决方案更容易理解。

array[Facilities, 0..max(d)] of var 0..max(C): facilityUsageAtTime;

constraint forall(i in Facilities) (
     forall(tt in 0..max(d)) (
        facilityUsageAtTime[i,tt] = sum(j in Tasks where x[j] == i /\ s[j] <= tt /\ tt < s[j] + p[x[j], j])(c[x[j],j]) /\
        facilityUsageAtTime[i,tt] <= C[i]
     )
);

受到@hakank回复发布here

的启发