iPad UIImagePicker问题！

Question

iam尝试从照片库导入图像，但是当我按下导入按钮程序崩溃并收到SGIBART !!但我的代码在iPhone上运行正常吗？

这是我的代码：

.h：

@interface CameraViewController : UIViewController <UIImagePickerControllerDelegate ,UINavigationControllerDelegate> {

    UIImagePickerController *ipc;
    UIImageView * image1;

@property (.......................;
}

.m：

    - (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info {



    image1.image = [[info objectForKey:UIImagePickerControllerOriginalImage]retain];
    [[picker parentViewController]dismissModalViewControllerAnimated:YES];
    [picker release];   

}


- (void)imagePickerControllerDidCancel:(UIImagePickerController *)picker {

    [[picker parentViewController]dismissModalViewControllerAnimated:YES];
    [picker release];


}



        -(IBAction) importImage1 {

    ipc = [[UIImagePickerController alloc]init];
    ipc.delegate = self;
    ipc.sourceType =  UIImagePickerControllerSourceTypePhotoLibrary;
    [self presentModalViewController:ipc animated:YES];
}

Answer 1

你正在崩溃，因为你正在释放选择器，但是你没有保留它。您应该删除对[picker release]的调用。

您应该切换到使用所有ivars的访问器。访问者和dealloc通常是您应该保留或释放您的ivars的唯一地方。选择器不是你的ivar而你没有创建它，所以你根本不应该发布它。

你应该花一些时间与Memory Management Programming Guide。您可以在Three Magic Words获得简短版本。

Answer 2

在iPad iOS 3.2上，UIImagePickerController必须以 popover 呈现，而不是模态视图。

检查一下： http://www.cocos2d-iphone.org/forum/topic/6108