Question

嘿伙计们我有这个代码：

sIP

我尝试解决了很多错误，但是没有带来任何好处！我创建了一个与libary一样的功能，现在我正在创建一个类。我需要帮助！这是错误：

#include<iostream>
#include<string>
#include<list>
#include<vector>

template<class T>
class ListLib {
public:
    ListLib(std::list<T>& listItem) {
        *listT = listItem;
    }

    std::vector<T> convertToVector() {
        std::vector<T> result;
        std::list<T>::iterator itList;

        for (itList = *listT->begin(); itList != *listT->end(); itList++)
            result->(*itList);

        std::vector<T>::iterator itVec;
        for (itVec = result.begin(); itVec != result.end())
            std::cout << *itVec << std::endl;
    }
private:
    std::list<T> *listT;
};

int main() {
    std::list<std::string> sampleList;
    std::vector<std::string> sampleVector;
    sampleList.push_back("3");
    sampleList.push_back("4");
    sampleList.push_back("5");
    sampleList.push_back("6");

    ListLib<std::string> listLib(sampleList);
    std::cout << "Hello World" << std::endl;
}

Answer 1

您缺少许多分号，并且在所有itterators之前还需要关键字typename ..这可以解决您遇到的所有问题：

#include<iostream>
#include<string>
#include<list>
#include<vector>

template<class T>
class ListLib {
public:
    ListLib(std::list<T>& listItem) {
        *listT = listItem;
    }

    std::vector<T> convertToVector() {
        std::vector<T> result;
        typename std::list<T>::iterator itList;

        for (itList = *listT->begin(); itList != *listT->end(); itList++)
                result.push_back(*itList);

        typename std::vector<T>::iterator itVec;
        for (itVec = result.begin(); itVec != result.end(); itVec++)
            std::cout << *itVec << std::endl;
    }
private:
    std::list<T> *listT;
};

int main() {
    std::list<std::string> sampleList;
    std::vector<std::string> sampleVector;
    sampleList.push_back("3");
    sampleList.push_back("4");
    sampleList.push_back("5");
    sampleList.push_back("6");

    ListLib<std::string> listLib(sampleList);
    std::cout << "Hello World" << std::endl;
}

/*template<class T>
void convertListToVector(std::list<T> *listItem, std::vector<T> *vectorConvert) {
std::list<T>::iterator it;
for (it = *listItem->begin(); it != *listItem->end(); it++)
*vectorConvert->push_back(*it);
}*/

工作 "C++ Fiddle"

错误：在迭代器之前需要'typename'

1 个答案: