Question

{"response":{"success":true,"access_token":"z5zbXVfaD4xOyTCLOwLIBPvuEYw7lQCUWb5U7l4KpCyXvbJkHv2jkyOZwk6RbJM7VS12d5NDImBeykygPBAa9o9FJgxUZk1Uc2Xp","access_level":"1"}}

如何单独解析响应？我想将每个对象都放在单独的变量中。我的代码：

var reponseError: NSError?
        var response: NSURLResponse?
        var urlData: NSData?


        do {
            urlData = try? NSURLConnection.sendSynchronousRequest(request, returningResponse:&response)
        }
        catch(let e) {
            print(e)
        }

        if ( urlData != nil ) {
            let res = response as! NSHTTPURLResponse!;

            NSLog("Response code: %ld", res.statusCode);

            if (res.statusCode >= 200 && res.statusCode < 300)
            {
                var responseData:NSString  = NSString(data:urlData!, encoding:NSUTF8StringEncoding)!

                NSLog("Response ==> %@", responseData);

Answer 1

对于简单的JSON解析，您可以使用NSJSONSerialization

var decodedJson : AnyObject
do {
    decodedJson = try NSJSONSerialization.JSONObjectWithData(urlData!, options: .MutableContainers)
}
catch (let e) {
    //Error in parsing
    print(e)
}

这将返回一个包含响应JSON的所有键/值对的Dictionary。您只需使用此字典即可获得所需密钥的值。

但是，更好的方法是为响应创建一个模型类。

在你的情况下，它可能是这样的：

class ResponseModel {

    var success : Bool?
    var accessToken : String?
    var accessLevel : Int?

    init(dictionary : NSDictionary) {

        if let successValue = dictionary["success"] as? Bool {
            success = successValue
        }
        if let accessTokenValue = dictionary["access_token"] as? String{
            accessToken = accessTokenValue
        }
        if let accessTokenValue = dictionary["access_level"] as? Int{
            accessLevel = accessTokenValue
        }
    }
}

然后，您可以更新代码以创建ResponseModel对象：

if (res.statusCode >= 200 && res.statusCode < 300)
{
    var responseData:NSString  = NSString(data:urlData!, encoding:NSUTF8StringEncoding)!

    NSLog("Response ==> %@", responseData);

    //JSON serialization
    var decodedJsonResponse : NSDictionary?
    do {

        decodedJsonResponse = try NSJSONSerialization.JSONObjectWithData(urlData!, options: .MutableContainers) as? NSDictionary
    }
    catch (let e) {
        //Error in parsing
        print(e)
    }

    //Use JSON response dictionary to initialize the model object
    if let decodedJson = decodedJsonResponse?["response"] as? NSDictionary {
        let responseObject = ResponseModel(dictionary: decodedJson)

        //use responseObject as required
        print(responseObject)
    }
}

如何在Swift中解析以下JSON？

1 个答案: