Question

这里我从本地资产文件夹中获取了JSON。所有JSON对象的名称都不同。 1号线，3号线，5号线，7号线......一直到1000号。我附上了json供你参考。

     {
    "status": {
        "rcode": 200,
        "message": "OK"
    },
    "data": {
        "0": {
            "OutletName": "Test 1 ",
            "Latitude": "16.123234",
            "Longitude": "79.546745"
        },
        "1": {
            "OutletName": "Test 2",
            "Latitude": "16.343234",
            "Longitude": "79.786745"
        },
        "2": {
            "OutletName": "Test 3",
            "Latitude": "19.1294",
            "Longitude": "72.836122"
        },
        "3": {
            "OutletName": "Test 4",
            "Latitude": "19.136383",
            "Longitude": "72.827997"
        },
        "6": {
            "OutletName": "Test 5",
            "Latitude": "19.136715",
            "Longitude": "72.829248"
        },
        "7": {
            "OutletName": "Test 6",
            "Latitude": "19.128483",
            "Longitude": "72.821199"
        },
        "8": {
            "OutletName": "Test 7",
            "Latitude": "19.128528",
            "Longitude": "72.819388"
        },
        "10": {
            "OutletName": "Test 8",
            "Latitude": "19.140333",
            "Longitude": "72.831095"
        },
        "11": {
            "OutletName": "Test 9",
            "Latitude": "19.14027",
            "Longitude": "72.826285"
        }
    }
}

这里对象名称对所有人都不同。所以我试试这个

private void parseJson() {
        try {
            JSONObject obj = new JSONObject(loadJSONFromAsset());
            JSONObject jObj = obj.getJSONObject("data");
            System.out.println("jObj.length()==> " + jObj.length());
            for (int i = 0; i < jObj.length(); i++) {

                if (jObj.has(String.valueOf(i)) && !jObj.isNull(String.valueOf(i))) {
                    JSONObject jObj1 = jObj.getJSONObject(String.valueOf(i));
                    System.out.println("Index==> "+i);
                    System.out.println("OutletName==> "+jObj1.getString("OutletName"));
                  }
            }

        } catch (JSONException e) {
            e.printStackTrace();
        }
    }

但在这里我没有获得所有数据。请帮我解析一下这种JSON。

提前致谢。

Answer 1

您需要使用keys方法，如下所示：

private void parseJson() {
    try {
        JSONObject obj = new JSONObject(loadJSONFromAsset());
        JSONObject jObj = obj.getJSONObject("data");
        Iterator iter = jObj.keys()
        while(iter.hasNext()) {
            String key = (String) iter.next();
            JSONObject jObj1 = jObj.getJSONObject(key);
            System.out.println("Index==> "+ key);
            System.out.println("OutletName==> "+jObj1.getString("OutletName"));
        }

    } catch (JSONException e) {
        e.printStackTrace();
    }
}

修改修复了一些类型转换

Answer 2

＆＃34;数据＆＃34;的价值在你的JSON中不是一个数组，因此你不能直接迭代它。您需要先将其转换为HashMap，然后迭代键集。您可以使用Jackson library将JSONObject转换为HashMap。您也可以参考this answer转换为地图。

Answer 3

首先，您必须对json响应进行更改

 {
    "status": {
        "rcode": 200,
        "message": "OK"
    },
    "data": {                   //this has to be array in your json

        "0": {                            //  and these are object inside the arrays
            "OutletName": "Test 1 ",
            "Latitude": "16.123234",
            "Longitude": "79.546745"
        },
        "1": {                                    //  and these are object inside the arrays
            "OutletName": "Test 2",
            "Latitude": "16.343234",
            "Longitude": "79.786745"
        },
        "2": {
            "OutletName": "Test 3",
            "Latitude": "19.1294",
            "Longitude": "72.836122"
        },
        "3": {
            "OutletName": "Test 4",
            "Latitude": "19.136383",
            "Longitude": "72.827997"
        },
        "6": {
            "OutletName": "Test 5",
            "Latitude": "19.136715",
            "Longitude": "72.829248"
        },
        "7": {
            "OutletName": "Test 6",
            "Latitude": "19.128483",
            "Longitude": "72.821199"
        },
        "8": {
            "OutletName": "Test 7",
            "Latitude": "19.128528",
            "Longitude": "72.819388"
        },
        "10": {
            "OutletName": "Test 8",
            "Latitude": "19.140333",
            "Longitude": "72.831095"
        },
        "11": {
            "OutletName": "Test 9",
            "Latitude": "19.14027",
            "Longitude": "72.826285"
        }
    }
}

并且不要超过json对象的大小来访问它的对象它必须是JSONArray 像这样

获取JSONArray中的数组数据

JSONArray dataArray = response_obj.getJSONArray("data");

然后像这样迭代

for (int i = 0; i < dataArray.length(); i++) 
{
   //write your code here to access all the object as for loop executes on by one
}

如何解析以下JSON

3 个答案: