我需要一个总和其他列的查询
mnist.train.next_batch()
按用户和日期过滤的日期之间的结果应该是:
2016年1月3日至2016年3月31日
User sales amount date
--------------------------------------
danny car 10.000 25/02/2016
danny moto 5.000 26/02/2016
danny car 10.000 25/03/2016
danny moto 5.000 26/03/2016
danny moto 5.000 26/03/2016
danny car 10.000 25/04/2016
danny moto 5.000 26/04/2016
danny car 10.000 25/05/2016
danny moto 5.000 26/05/2016
我需要什么查询?
答案 0 :(得分:1)
尝试Pivot
SELECT * FROM
(
SELECT User,sales,amount,datename(month, date)
FROM YoyrTable
)A
PIVOT
(
SUM(amount)
FOR sales in ([car],[moto])
)B
答案 1 :(得分:1)
另一种方法:
;WITH cte AS (
SELECT *
FROM (VALUES
('danny', 'car', 10.000, '2016-02-15'),
('danny', 'moto', 5.000, '2016-02-26'),
('danny', 'car', 10.000, '2016-03-25'),
('danny', 'moto', 5.000, '2016-03-26'),
('danny', 'moto', 5.000, '2016-03-26'),
('danny', 'car', 10.000, '2016-04-25'),
('danny', 'moto', 5.000, '2016-04-26'),
('danny', 'car', 10.000, '2016-05-25'),
('danny', 'moto', 5.000, '2016-05-26')
) as t([User], sales, amount, [date])
)
SELECT [user],
SUM(amount) as Total,
SUM(CASE WHEN sales = 'moto' THEN 1 ELSE 0 END) as moto,
SUM(CASE WHEN sales = 'car' THEN 1 ELSE 0 END) as car,
DATENAME(Month,[date]) as [date]
FROM cte
GROUP BY [user], DATENAME(Month,[date]),DATEPART(Month,[date]), DATEPART(Year,[date])
ORDER BY DATEPART(Month,[date]), DATEPART(Year,[date])
输出:
user Total moto car date
danny 15.000 1 1 February
danny 20.000 2 1 March
danny 15.000 1 1 April
danny 15.000 1 1 May
在查询中,将您的表名改为cte
答案 2 :(得分:1)
您的实际PIVOT
应该是什么样的..
SELECT [User],
Total,
[moto],
[car],
[date]
FROM
(
SELECT [User],
sales,
DATENAME(MONTH,date) [date],
SUM(amount) OVER (PARTITION BY [User], DATENAME(MONTH,date)) [Total]
FROM cte
) T
PIVOT
(
COUNT(sales)
FOR sales IN ([car], [moto])
) p
@ gofr1的回答应该会更好。