Question

我有一个包含3个属性的表：

Title          TotalNumberOfAuthors              TotalNumberOfPublishedAuthors
A                    3                                         1
B                    2                                         2
C                    4                                         2
D                    2                                         1

我正在尝试创建一个查询，显示 TotalNumberOfPublishedAuthors 的总和以及 TotalNumberOfNonPublishedAuthors 的总和，即（TotalNumberofAuthors - TotalNumberOfPublishedAuthors）..

这是我生成的查询，但没有按预期显示结果：

SELECT SUM(Submission.TotalNumberOfPublishedAuthors),        
       (SUM(Submission.TotalNumberOfAuthors) - SUM(Submission.TotalNumberOfPublishedAuthors)) AS Number_of_Non_Published_Authors
FROM Submission INNER JOIN ((Faculty INNER JOIN School 
ON Faculty.FacultyID = School.[FacultyID]) INNER JOIN (Researcher INNER JOIN ResearcherSubmission 
ON Researcher.ResearcherID = ResearcherSubmission.ResearcherID) 
ON School.SchoolID = Researcher.SchoolID) 
ON Submission.SubmissionID = ResearcherSubmission.SubmissionID;

这是我想要的结果：

TotalNumberofPublishedAuthors                     TotalNumberofPublishedAuthors
         6                                                     5

Answer 1

SELECT <Column Names>
FROM <Table Name>
UNION ALL
SELECT NULL,SUM(<Column name>),null,sum(<RunningTotal or AnyTotal>)
FROM <Table Name>

Answer 2

如果您确实在[Submission]表中有[TotalNumberOfPublishedAuthors]和[TotalNumberOfAuthors]的列，那么就不需要加入任何其他表。只需执行查询中已有的总和，但不需要进一步的表格。

SQL Fiddle

MS SQL Server 2014架构设置：

CREATE TABLE Submission
    ([Title] varchar(1), [TotalNumberOfAuthors] int, [TotalNumberOfPublishedAuthors] int)
;

INSERT INTO Submission
    ([Title], [TotalNumberOfAuthors], [TotalNumberOfPublishedAuthors])
VALUES
    ('A', 3, 1),
    ('B', 2, 2),
    ('C', 4, 2),
    ('D', 2, 1)
;

查询1 ：

SELECT
      SUM(Submission.TotalNumberOfPublishedAuthors) AS TotalNumberOfPublishedAuthors
    , SUM(Submission.TotalNumberOfAuthors) 
    - SUM(Submission.TotalNumberOfPublishedAuthors) AS Number_of_Non_Published_Authors
FROM Submission

<强> Results ：

| TotalNumberOfPublishedAuthors | Number_of_Non_Published_Authors |
|-------------------------------|---------------------------------|
|                             6 |                               5 |

使用SQL Query计算总计

2 个答案: