Question

@Entity
@Table(name="sometable_citylocation")
public class CityLocation extends Model implements Serializable {


    private int cityDestinationId;

    @ManyToOne
    @JoinColumn(name="cityDestinationId", referencedColumnName="destinationId")
    private City city;

我有这种关系，我可以通过定义的映射轻松获得城市，但我还需要能够直接设置和更改cityDestinationId，因为它是由外部源提供给我的。

我需要做什么注释才能做到这一点而不会丢失任何功能（将城市作为对象，能够从字段/ getter / setter设置/更改/获取id）

线程“main”中的异常 org.springframework.beans.factory.BeanCreationException：错误创建名为'modelDao'的bean：注入自动装配依赖失败;嵌套异常是 org.springframework.beans.factory.BeanCreationException：不能 autowire字段：private org.hibernate.SessionFactory nl.exit.crunch.dao.AbstractDao.sessionFactory;嵌套异常是 org.springframework.beans.factory.BeanCreationException：错误在类路径中定义名为'sessionFactory'的bean resource [nl / exit / crunch / config / HibernateConfiguration.class]：调用init方法失败;嵌套异常是 org.hibernate.MappingException：实体映射中的重复列： nl.exit.crunch.table.some.destination.CityLocation列： cityDestinationId（应使用insert =“false”进行映射更新= “假”）

Answer 1

The answer is to add insertable and updateable to the object mapping

@JoinColumn(name="cityDestinationId",
            insertable=false, 
            updatable=false, 
            referencedColumnName="destinationId"
        )

Keep in mind that you cannot use the object to bind/unbind relations. This is not relevant in my case since the foreign key will be supplied from external source. All i care about is getting the object out

如何在定义关系的同时直接访问映射字段

1 个答案: