Question

我有一个XML文件，其中包含一些节点及其子节点，有时具有相同的名称和属性。

<?xml version="1.0"?>
<PurchaseOrder PurchaseOrderNumber="99503" OrderDate="1999-10-20">
  <Address Type="Shipping">
    <Name>Ellen Adams</Name>
    <Street>123 Maple Street</Street>
    <City>Mill Valley</City>
    <State>CA</State>
    <Zip>10999</Zip>
    <Country>USA</Country>
  </Address>
  <Address Type="Billing">
    <Name>Tai Yee</Name>
    <Street>8 Oak Avenue</Street>
    <City>Old Town</City>
    <State>PA</State>
    <Zip>95819</Zip>
    <Country>USA</Country>
    <Address Type="Buying">
        <Name>Ellen Adams</Name>
    </Address>
    <Address Type="transporting">
        <Name>Tai Yee</Name>
        <Street>8 Oak Avenue</Street>
    </Address>
  </Address>
  <DeliveryNotes>Please leave packages in shed by driveway.</DeliveryNotes>
  <Items>
    <Item PartNumber="872-AA">
      <ProductName>Lawnmower</ProductName>
      <Quantity>1</Quantity>
      <USPrice>148.95</USPrice>
      <Comment>Confirm this is electric</Comment>
    </Item>
    <Item PartNumber="926-AA">
      <ProductName>Baby Monitor</ProductName>
      <Quantity>2</Quantity>
      <USPrice>39.98</USPrice>
      <ShipDate>1999-05-21</ShipDate>
    </Item>
  </Items>
</PurchaseOrder>

我希望只有Address个节点及其属性作为输出。问题是有一些嵌套节点将Address节点作为子节点。访问孩子Address是我的问题。如果它再次具有名为Address的子节点，那么我不想像我在以下代码中那样给我这个节点

public void find_node(string ID_node) 
{
    XElement root = XElement.Load("PurchaseOrder.xml");
    IEnumerable<XElement> address =
        from el in root.Elements("Address")
        where (string)el.Attribute("Type") == "Buying"
        select el;

    foreach (XElement el in address)
    {
        var newElement = new XElement(
                                el.Name.LocalName,
                                el.Attributes(),
                                el.Elements().Where(o => o.Name.LocalName != "Address")
                         );
        Console.WriteLine(newElement.ToString());
    }
}

此代码的所需输出为

<Address Type="Buying">
    <Name>Ellen Adams</Name>
</Address>

但是当我运行上述函数时它的输出为空。

我可以问你能为这个功能获得空输出吗？

Answer 1

如果您要查找Address元素，无论其在XML中的位置如何，只要它与属性过滤器匹配，您就可以使用Descendants("Address")代替：

IEnumerable<XElement> address =
                from el in root.Descendants("Address")
                where (string)el.Attribute("Type") == "Buying"
                select el;

Answer 2

IEnumerable<XElement> address =
            from el1 in root.Elements("Address")
            from el2 in el1.Elements("Address")
            where (string)el2.Attribute("Type") == "Buying"
            select el2;

在XML中为选定节点提供空输出

2 个答案: