Question

我有table_1和table_2，它们是相同的结构，但数据不同。需要以create_date的排序从表中获取所有数据，无论从哪个表（它可以是table_1中的1行，table_2中的3行，然后再来自table_1）。可能吗？怎么样？或者喊我得到两个查询，然后用PHP按日期排序？

编辑：对不起，第一部分，我以为我可以从那里做，但似乎我不能：/

我有像这样的非常大的查询

SELECT 
    table_1.id, 
    table_1.created, 
    table_1.qty, 
    table_1.comments, 
    table_1.last_update, 
    table_7.firstname, 
    SUBSTRING(table_7.lastname, 1, 1) AS lastname, 
    table_8.title country, 
    table_3.value AS sim, 
    table_1.offer_request, 
    table_5.manufacturer AS manufacturer, 
    table_4.name AS model, 
    table_6.value AS specifications, 
    table_9.value as shipping, 
    table_1.model AS mid, 
    table_1.user_id, 
    table_1.callme, 
    table_1.phoneprice, 
    table_1.phoneprice_eur, 
    table_1.currency, 
    table_1.sel_buy_show_all, 
    table_1.seller_buyer
FROM (`table_1`)

LEFT JOIN `table_3` ON `table_3`.`id` = `table_1`.`sim`
LEFT JOIN `table_4` ON `table_4`.`id` = `table_1`.`model`
LEFT JOIN `table_5` ON `table_5`.`id` = `table_1`.`manufacturer`
LEFT JOIN `table_6` ON `table_6`.`id` = `table_1`.`specifications`
LEFT JOIN `table_7` ON `table_7`.`id` = `table_1`.`user_id`
LEFT JOIN `table_8` ON `table_7`.`country`=`table_8`.`id`
LEFT JOIN `table_9` ON `table_9`.`id` = `table_1`.`types`
WHERE `table_1`.`status` =  '1'
AND `table_1`.`deleted` =  '0'
ORDER BY `last_update` DESC
LIMIT 200

还有table_1哪个结构与table_2相同，我需要以某种方式将table_2插入到包含所有连接的查询中，如table_1

Answer 1

如果我的问题是对的，你可以使用这样的联盟 -

select * from table_1 union select * from table_2 order by create_date desc

修改

创建一个这样的视图 -

create view table_1And2 as select * from table_1 union select * from table_2

table_1And2不是一个好名字，给出一个有意义的名字。

并像这样修改你的长查询 -

SELECT table_1And2.id, table_1And2.created, table_1And2.qty, table_1And2.comments, table_1And2.last_update, table_7.firstname, SUBSTRING(table_7.lastname, 1, 1) AS lastname, table_8.title country, table_3.value AS sim, table_1And2.offer_request, table_5.manufacturer AS manufacturer, table_4.name AS model, table_6.value AS specifications, table_9.value as shipping, table_1And2.model AS mid, table_1And2.user_id, table_1And2.callme, table_1And2.phoneprice, table_1And2.phoneprice_eur, table_1And2.currency, table_1And2.sel_buy_show_all, table_1And2.seller_buyer FROM (`table_1And2`) LEFT JOIN `table_3` ON `table_3`.`id` = `table_1And2`.`sim` LEFT JOIN `table_4` ON `table_4`.`id` = `table_1And2`.`model` LEFT JOIN `table_5` ON `table_5`.`id` = `table_1And2`.`manufacturer` LEFT JOIN `table_6` ON `table_6`.`id` = `table_1And2`.`specifications` LEFT JOIN `table_7` ON `table_7`.`id` = `table_1And2`.`user_id` LEFT JOIN `table_8` ON `table_7`.`country`=`table_8`.`id` LEFT JOIN `table_9` ON `table_9`.`id` = `table_1And2`.`types` WHERE `table_1And2`.`status` = '1' AND `table_1And2`.`deleted` = '0' ORDER BY `last_update` DESC LIMIT 200

Answer 2

另外我看到@Rehban的答案对你来说很好，如果你不需要view，我会提出另一个解决方案：

SELECT 
mainTable.id, 
mainTable.created, 
mainTable.qty, 
mainTable.comments, 
mainTable.last_update, 
table_7.firstname, 
SUBSTRING(table_7.lastname, 1, 1) AS lastname, 
table_8.title country, 
table_3.value AS sim, 
mainTable.offer_request, 
table_5.manufacturer AS manufacturer, 
table_4.name AS model, 
table_6.value AS specifications, 
table_9.value as shipping, 
mainTable.model AS mid, 
mainTable.user_id, 
mainTable.callme, 
mainTable.phoneprice, 
mainTable.phoneprice_eur, 
mainTable.currency, 
mainTable.sel_buy_show_all, 
mainTable.seller_buyer
FROM (Select * From `table_1` union Select * From `table_2`) as mainTable

LEFT JOIN `table_3` ON `table_3`.`id` = `mainTable `.`sim`
LEFT JOIN `table_4` ON `table_4`.`id` = `mainTable `.`model`
LEFT JOIN `table_5` ON `table_5`.`id` = `mainTable `.`manufacturer`
LEFT JOIN `table_6` ON `table_6`.`id` = `mainTable `.`specifications`
LEFT JOIN `table_7` ON `table_7`.`id` = `mainTable `.`user_id`
LEFT JOIN `table_8` ON `table_7`.`country`=`table_8`.`id`
LEFT JOIN `table_9` ON `table_9`.`id` = `mainTable `.`types`
WHERE `mainTable `.`status` =  '1'
AND `mainTable `.`deleted` =  '0'
ORDER BY `last_update` DESC
LIMIT 200

从MySQL两个表中获取数据和排序

2 个答案: