两个表 - posts
- 和users
,公共列 - posts.user / users.id
我需要输出一些统计数据,即每个用户今天有多少帖子,持续7-30-365天和总计数。
下面的代码有效,但如果可能的话,我很有兴趣减少查询次数。
$stmt0 = $db->query("select * from users where role = 'mod' order by name asc");
$count0 = $stmt0->rowCount();
while($row0 = $stmt0->fetch()){
$stmt1 = $db->query("select id from posts where user = " . $row0['id'] . " and date(date) = date(now())");
$stmt2 = $db->query("select id from posts where user = " . $row0['id'] . " and date(date) > curdate() - interval 7 day");
$stmt3 = $db->query("select id from posts where user = " . $row0['id'] . " and date(date) > curdate() - interval 30 day");
$stmt4 = $db->query("select id from posts where user = " . $row0['id'] . " and date(date) > curdate() - interval 365 day");
$stmt5 = $db->query("select id from posts where user = " . $row0['id']);
}
$count1 = $stmt1->rowCount();
$count2 = $stmt2->rowCount();
... etc.
答案 0 :(得分:1)
MySQL查询:
SELECT
user,
COUNT(DISTINCT CASE WHEN date = CURDATE() THEN id END) as countToday,
COUNT(DISTINCT CASE WHEN date >= CURDATE() - INTERVAL 7 DAY THEN id END) as count7,
COUNT(DISTINCT CASE WHEN date >= CURDATE() - INTERVAL 14 DAY THEN id END) as count14,
COUNT(DISTINCT CASE WHEN date >= CURDATE() - INTERVAL 30 DAY THEN id END) as count30,
COUNT(DISTINCT CASE WHEN date >= CURDATE() - INTERVAL 365 DAY THEN id END) as count365,
COUNT(*) as countAll
FROM posts
GROUP BY posts.user
使用PHP访问:
$res = $db->query($query); // set $query to my query
while($row = $res>fetch()){ // loop the result
// access your row here
echo $row["user"] // $row["countToday"] ...
}