这是我一直在学习C ++的程序。它将文件输入两个不同的数组(字符串,2d double),而不是排序,平均值,将平均值添加到2d双数组的末尾而不是输出。我试图实现一个搜索(最好是二进制),找到与searchItem变量匹配的名称,而不是获取与该名称相关联的分数来输出。我知道如何实现抓取分数。将变量存储到变量中,找到名称的元素位置,并使用它来引用正确分数所在的行。像二进制搜索一样出现问题不会产生编译错误,也不会做任何事情。根据我的理解,我使用的算法与我见过的其他算法相同。我是否在正确的轨道上有我的想法或有更好的方法?在我看来,这是最简单的方式,但我对这种语言的经验是有限的。提前谢谢。
<table>
<?php
$items = WC()->cart->get_cart();
// Here begins the cart loop
foreach($items as $item => $values) {
$_product = $values['data']->post;
$product_id = $values['product_id']; // product Id
$product_title = $_product->post_title // product title
$product_price = get_post_meta($product_id , '_price', true); // product price
$product_qty = $values['quantity']; // product quantity
$productDetails = wc_get_product( $product_id ); // product details array
// Here in this foreach loop you display each product of the cart
?>
<tr>
<td><?php echo $product_title; ?></td>
<td><?php echo $product_qty; ?></td>
<td><?php echo $product_price; ?></td>
</tr>
<?php
}
?>
</table>
输入文件:bowlers2.txt
#include <stdlib.h>
#include <iostream>
#include <iomanip>
#include <fstream>
#include <string>
using namespace std;
const int ROWS = 11;
const int COLS = 4;
void ArrayManip (string x[], double y[][COLS], int length);
int main()
{
ifstream inFile;
inFile.open("bowlers2.txt");
const int SIZE = 10;
double scores[ROWS][COLS];
string names[SIZE];
string mystring;
if (!inFile)
{
cout << "Can not open the input file"
<< " This program will end."<< "\n";
return 1;
}
for(int r = 0; r < SIZE; r++)
{
getline(inFile, names[r]);
for(int c = 0; c < (COLS - 1); c++)
{
getline(inFile, mystring);
scores[r][c] = atoi(mystring.c_str());
}
}
inFile.close();
ArrayManip (names, scores, SIZE);
return 0;
}
void ArrayManip (string x[], double y[][COLS], int LENGTH)
{
int i,j,k,
first = 0,
last = LENGTH - 1,
middle,
position = -1;
bool found = false;
string searchItem = "keith";
string sValue;
double dValue;
double dArray[COLS - 1];
double sum = 0;
double avr;
//Sort names and scores
for(i = 1; i < LENGTH; i++)
{
sValue = x[i];
for (k = 0; k < (COLS - 1); k++)
{
dArray[k] = y[i][k];
}
for(j = i - 1; j >= 0 && x[j] > sValue; j--)
{
x[j + 1] = x[j];
for (k = 0; k < (COLS - 1); k++)
{
y[j + 1][k] = y[j][k];
}
}
x[j + 1] = sValue;
for (k = 0; k < (COLS - 1); k++)
{
y[j + 1][k] = dArray[k];
}
}
for(k = 0; k < LENGTH; k++)
for(i = 1; i < (COLS - 1); i++)
{
dValue = y[k][i];
for(j = i - 1; j >= 0 && y[k][j] > dValue; j--)
{
y[k][j + 1] = y[k][j];
}
y[k][j + 1] = dValue;
}
//average and store rows
for(i=0;i<LENGTH;i++)
{
for(j = 0; j < (COLS - 1); j++)
{
sum += y[i][j];
}
avr = sum/(COLS -1);
y[i][j++] = avr;
sum = 0;
}
//average and store columns
for(j=0;j<(COLS - 1);j++)
{
for(i=0;i<LENGTH;i++)
{
sum += y[i][j];
}
avr = sum/LENGTH;
y[i++][j] = avr;
sum = 0;
}
cout << fixed << showpoint << setprecision(2);
cout << "Averages for all Players:\n";
for(i=0;i<(COLS - 1);i++)
{
cout << "Score " << (i+1) << " average: " << y[LENGTH][i] << "\n";
}
cout << "\n";
for(i=0;i<LENGTH;i++)
{
cout << "player " << (i+1) << ": " << x[i] << "\n";
for(j=0;j<COLS;j++)
{
if(j < (COLS - 1))
{
cout << "score " << (j+1) << ": " << y[i][j] << "\n";
}
else
cout << "player average: " << y[i][j] << "\n\n";
}
}
while(!found && first <= last)
{
middle = (first + last) / 2;
if(x[middle] == searchItem)
{
found = true;
cout << x[middle] << "\n";
}
else if (x[middle] > searchItem)
last = middle - 1;
else
first = middle + 1;
}
}
答案 0 :(得分:1)
使用等于运算符比较两个std::string
对象时,它会比较整个字符串。如果您正在寻找"keith"
并将其与字符串"keith hallmark"
进行比较,那么它将无法匹配。
您可以使用std::string::find
在字符串中查找子字符串。
像
if (x[middle].find(searchItem) != std::string::npos)
{
// Sub-string found
}