Question

数组已经排序。

然后我要求用户输入一个名称，以便可以在数组中搜索＆＃34; names＆＃34;。这样做的目的是让我可以得到名称的索引，这样我就可以从2D数组输出相应的分数＆＃34;得分＆＃34;。

这些是我的阵列：

String[] names = new String[10];
int[][] scores = new int[10][3];

这里是二元搜索：

System.out.println("Which student's scores do you want to see?");

    String name = scnr.nextLine();
    scnr.nextLine();

    int index = Arrays.binarySearch(names, name);

    System.out.println(index);

我打印索引只是为了检查它是否正确，但我看到它打印出-1。我正确输入输入，没有空格和正确大写。我不确定我做错了什么。

这是我的代码：

import java.util.Scanner;
import java.util.Arrays;

/**
*Write a program that will input 10 students names
* in random order and their corresponding 3 project scores.
* Data will be read into 2 separate arrays: an array of strings
* for the names and a 2D array for the scores.
* Output input data in table form
*Using Binary Search your program will accept user input (name) and output  
*the name and its corresponding 3 project scores.
*For each of the 3 projects, output the name of the student(s) who scored
the highest mark.
**/

class NameAndGrades {
    public static void main(String[] args) {
        //Scanner object to allow user input
        Scanner scnr = new Scanner(System.in);

        //This array will store the names of the students
         String[] names = new String[10];

    //This 2D array will store the 3 project scores
    int[][] scores = new int[10][3];


    //Ask user to input the student names
    System.out.println("Enter the 10 student names: ");

    for (int index = 0; index < 10; index++) {
        System.out.print("Student " + (index + 1) + ": ");
        names[index] = scnr.nextLine();
    }


    //Ask user to enter the corresponding project scores

    System.out.println("\nEnter the 3 project grades for each student:\n");

    for(int i = 0; i < names.length; ++i)
    {
     System.out.print("   Enter three project grades for " + names[i] + " :   ");
     scores[i][0] = scnr.nextInt();
     scores[i][1] = scnr.nextInt();
     scores[i][2] = scnr.nextInt();
     }



    System.out.println("Which student's scores do you want to see?");
    String name = scnr.nextLine();
    scnr.nextLine();

    int index = Arrays.binarySearch(names, name);

    System.out.println(index);
}



/**Selection sort method made to sort the student names in
* alphabetical order.
@param names names of students
@return the names organized alphabetically
*/

public static String[] selectionSort(String[] names) {
    for (int index = 0; index < names.length - 1; ++index) {
        int minIndex = index;
        for (int j = index + 1; j < names.length; ++j) {
            if (names[j].compareTo(names[minIndex]) < 0) {
                minIndex = j;
            }
        }
        String temp = names[index];
        names[index] = names[minIndex];
        names[minIndex] = temp;
    }
    return (names);
}

以下只是一个可能的替代方案，我的主要问题是为什么我得到-1的指数

除非我可以使用这样的东西进行二进制搜索，否则我从本书中得到了这个例子（但是我需要帮助更改它以便它可以用于String数组）：

public static int binarySearch(String[] names, String name)
{
  int first = 0;
  int last = names.length - 1;
  int mid;
  int position = -1;
  boolean found = false;

  while(!found && first <= last)
  {
    mid = (first + last)/2;
    if (names[mid] == name)
    {
      found = true;
      position = mid;
    }
    else if (names[mid] > name)
      last = mid - 1;
    else
      first = mid - 1;
  }
  return position;
}

Answer 1

为什么使用原始数组？您应该使用从学生姓名到学生分数的地图。然后，您可以使用API调用轻松找到它们。例如：

Map<String, List<Integer>> studentMarks = new HashMap(10);
String targetStudent;

//... perform initialization here

System.out.println(studentMarks.get(targetStudent));

二进制搜索字符串数组，返回-1

1 个答案: