Question

我在谷歌搜索但没有找到任何修复程序......以下是代码：

public Command getCommandbyAlias(String alias)
{
    int length;
    int i;
    for (Iterator localIterator = getCommands().iterator(); localIterator.hasNext(); i < length)  //Here, at i < length
    {
        Command cmd = (Command)localIterator.next();
        String[] alias2;
        length = (alias2 = cmd.getAlias()).length;
        i = 0;
        continue;

        String aliases = alias2[i];
        Utils.addChatMessage(aliases);
        if (aliases.equalsIgnoreCase(alias)) {
            return cmd;
        }
        i++;
    }
    return null;
}

Answer 1

for循环中的第三个参数不正确。我猜你想要这样的东西：

for (Iterator localIterator = getCommands().iterator(); localIterator.hasNext() && i < length; )

Answer 2

根据oracle doc s

class A(object):
    def __init__(self, y):
        self.x = 2
        self.y = y

class B(A):
    def __init__(self, y, z):
        super().__init__(y)  # equivalent to: A.__init__(self, y)
        self.z = z

b = B(3, 4)
# b's x is 2, b's y is 3 (both set by A.__init__, the last one was passed by B), and b's z is 4 (set by B.__init__)

第三个论点是为增量/减量语句保留的，它是可选的

如果您对使用for循环感到困惑，请按以下代码

转到

for (initialization; termination;
     increment) {
    statement(s)
}

while

Answer 3

如果在for语句中需要两个条件，则应使用&&布尔运算符将它们连接到单个条件：

for (Iterator localIterator = getCommands().iterator(); 
     localIterator.hasNext() && i < length) {

顺便说一句，请注意，在尝试使用它们之前，应初始化i和length。你当前的代码没有。

Answer 4

试试这个：

public Command getCommandbyAlias(String alias)
{
    int length;
    int i;
    Iterator localIterator = getCommands().iterator();
    while (localIterator.hasNext() && i < length)
    {
        Command cmd = (Command)localIterator.next();
        String[] alias2;
        length = (alias2 = cmd.getAlias()).length;
        i = 0;
        continue;

        String aliases = alias2[i];
        Utils.addChatMessage(aliases);
        if (aliases.equalsIgnoreCase(alias)) {
            return cmd;
        }
        i++;
    }
    return null;
}

令牌上的语法错误＆＃34;＆lt;＆＃34;，无效的AssignementOperato

4 个答案: