Question

我正在尝试创建一个简单的单词拼字游戏脚本，用于查找单词得分值。脚本应从命令行读取两个参数并显示最佳字值，该值返回具有最高点值的字。我创建了一个构造函数，它读取文件并填充字母/值的字典，以便与该类的其余方法一起使用。例如，命令行参数应如下所示：

scrabble.py c:\tiles.txt apple,squash  
Output: The best value is squash with 18.

这是我到目前为止所拥有的。我知道import argv很有用，但不知道如何开始。

from sys import argv

class Scrabble:
    def __init__(self, tilesFile):
        with open(tilesFile, "r") as f:
            lines = [ line.strip().split(":") for line in f ]

        self.tiles = { k:int(v) for k,v in lines }

    def getWordValue(self, word):
        sum = 0
        for letter in word.upper():
            sum += self.tiles[letter]

        return sum

    def getBestWord(self):
        pass


def main():
    s1 = Scrabble("tile_values.txt")
    value = s1.getWordValue("hello")
    print(value)


if __name__ == '__main__':
   main()
   pass

Answer 1

~~您需要的是使用argparse模块 https://docs.python.org/3/library/argparse.html~~

~~<击>~~

~~我举了你的例子并添加了argparse。~~你的Scrabble构造函数存在一些问题。但是你会想到在命令行上使用args

python scrabble.py tiles.txt apple squash orange

import argparse
import sys

class Scrabble:
    def __init__(self, tilesFile):
        with open(tilesFile, "r") as f:
            lines = [ line.strip().split(":") for line in f ]

        self.tiles = { k:int(v) for k,v in lines }

    def getWordValue(self, word):
        sum = 0
        for letter in word.upper():
            sum += self.tiles[letter]

        return sum

    def getBestWord(self):
        pass


def main(argv):
    s1 = Scrabble(argv[1])
    if len(argv) < 3:
        print 'no words given'
        sys.exit(1) 

    # argv[2:] means the items in argv starting from the 3rd item.
    # the first item will be the name of the script you are running
    # the second item should be the tiles file. 
    for word in argv[2:]:
        value = s1.getWordValue(word)
        print(value)


if __name__ == '__main__':
   main(argv)

Answer 2

您可以使用sys.argv获取脚本在命令行上传递的参数。

from sys import argv
print("This is a list of all of the command line arguments: ", argv)

使用python的简单单词拼字游戏代码，它接受命令行参数

2 个答案: