Question

我有以下SQL语句：

DELETE FROM Menu WHERE restaurantID = '2' AND foodID = '12';

我一直收到错误＆＃34;＃1046 - 没有选择数据库＆＃34;每当我尝试运行它。我查看了W3学校的示例SQL语句，看起来我的声明中包含了所有必要的部分。

Answer 1

DELETE FROM your_database_name.Menu WHERE restaurantID = '2' AND foodID = '12';

Answer 2

此代码可以帮助您与mysql和php进行交互

$link = mysqli_connect("localhost", "UserName","password", "databaseName");
$sql="delete from Table_name where restaurantID = '2' AND foodID = '12' ";

$del = mysqli_query($link, $sql);

    mysqli_close($link);
    if ($del) {
        echo "deleted ";
    } else {
        echo "did not delete ";
    }

注意：您运行服务器因为我认为你没有选择数据库忘记使用上面的代码很简单我希望我帮助你祝你好运

PHP myAdmin中没有数据库选择错误

2 个答案: