Question

在Firebird 2.5服务器DB上有表：商品，收入，销售货物表有列：goods_id，名称
收入：Income_id，Goods_id，incomeqty（数量），recdate
销售：sales_id，income_id，Goods_id，saleqty，recdate

我有查询在日期间隔中选择它们之间的收入，销售和差异，并且它可以正常工作：

select income.goods_id,
  sum(case when which = 'income' then sum_amt else 0 end) as sum_income,
  sum(case when which = 'sale' then sum_amt else 0 end) as sum_sale,
  sum(case when which = 'income' then sum_amt else 0 end)
  - sum(case when which = 'sale' then sum_amt else 0 end) as differ_between
from (select goods_id, sum(incomeqty) as sum_amt, 'income' as which
     from income
    where income.recdate betwwen :d1 and :d2         
    group by pr_k
   union all
   select goods_id, sum(salesqty), 'sale'
     from sales
     where sale.recdate between :d1 and :d2 
    group by goods_id) x
group by goods_id

但我想从商品表中另外选择商品名称。如何包括＆＃34; name＆＃34;此查询中的column和if子句（＆＃34; where goods_id = income.goods_id＆＃34;）？

Answer 1

简单添加联接

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但我不知道如果不包括收入，您发布的查询如何工作“select income.goods_id”？

修改后的版本以支持您的评论

select x.goods_id, G.name,
  sum(case when which = 'income' then sum_amt else 0 end) as sum_income,
  sum(case when which = 'sale' then sum_amt else 0 end) as sum_sale,
  sum(case when which = 'income' then sum_amt else 0 end)
 - sum(case when which = 'sale' then sum_amt else 0 end) as differ_between
from (select goods_id, sum(incomeqty) as sum_amt, 'income' as which
     from income
    where income.recdate betwwen :d1 and :d2         
    group by pr_k
   union all
   select goods_id, sum(salesqty), 'sale'
     from sales
     where sale.recdate between :d1 and :d2 
    group by goods_id) x 
    INNER JOIN GOODS G ON G.goods_id=x.goods_id
group by x.goods_id, G.name

但我想更好的是将“group by”和“select”中的字段顺序更改为：

select x.goods_id, G.name,
  sum(case when which = 'income' then sum_amt else 0 end) as sum_income,
  sum(case when which = 'sale' then sum_amt else 0 end) as sum_sale,
  sum(case when which = 'income' then sum_amt else 0 end)
 - sum(case when which = 'sale' then sum_amt else 0 end) as differ_between
from 
    GOODS G LEFT JOIN
    (select goods_id, sum(incomeqty) as sum_amt, 'income' as which
     from income
    where income.recdate betwwen :d1 and :d2         
    group by pr_k
   union all
   select goods_id, sum(salesqty), 'sale'
     from sales
     where sale.recdate between :d1 and :d2 
    group by goods_id) x ON G.goods_id=x.goods_id
group by x.goods_id, G.name

在Firebird

1 个答案: