Question

此请求向我提供EMAIL发生的请求发生次数。

    select count(*) 
    from ADRESS K left outer join ADRESS L 
       on K.LFDNRSECONDADRESS=L.LFDNR 
    left outer join ADRESS V 
       on K.VERLFDNR=V.LFDNR 
    where ((UPPER(K.EMAIL)= 'my@email.com' 
       or exists (select ADRESSEMAILADR.LFDNR 
                  from ADRESSEMAILADR 
                  where ADRESSEMAILADR.ADRESSLFDNR=K.LFDNR 
                     and UPPER(ADRESSEMAILADR.EMAIL)= 
                                'my@email.com' )
    )) and K.ART='K'

但我也希望得到所有出现的“LFDNR”列。

喜欢

所以第一个是计数，后续是LFDNR = X的所有列的结果。

我试过的原因

LFDNR, select count(*)  
K.LFDNR, select count(*)

依旧...... 到目前为止没有运气。

Answer 1

如果我理解正确，您需要group by：

select k.LFDNR, count(*) 
from ADRESS K left outer join
     ADRESS L 
     on K.LFDNRSECONDADRESS = L.LFDNR left outer join
     ADRESS V 
    on K.VERLFDNR = V.LFDNR 
 where (UPPER(K.EMAIL)= 'my@email.com' or
        exists (select ADRESSEMAILADR.LFDNR 
                from ADRESSEMAILADR 
                where ADRESSEMAILADR.ADRESSLFDNR = K.LFDNR and
                      UPPER(ADRESSEMAILADR.EMAIL) = 'my@email.com'
               )
       ) and
       K.ART = 'K'
 group by k.LFDNR;

select count（）如何添加列

1 个答案: