short assigned（final int）有效但传递（final int）作为短参数的参数不起作用

Question

查看以下代码，请帮助

class ShortExample{
final int x=9;
int m=9;
short s=x; // works fine as it is a compile time constant
short ss=9; // also works as compiler handles it
// short sss=m; // doesn't work due to possible loss of precision

ShortExample.play(x); // why doesn't this work
ShortExample.play(9);  // why doesn't this work 

static void play(short s){
//do something
}


}

这里当我为短变量分配最终的int值时，它会编译而没有问题。但是如果我传递与参数相同的值，则会导致精度编译错误。它不应该工作，因为它是一个恒定的值吗？